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AfilCa [17]
3 years ago
13

In 2012 the population of a herd of elk was 220 between 2012 and 2013 the population decreased by 10% between 2013 and 2014 the

population increased by 10% what was the population of the herd in 2014 rounded to the nearest whole number
Mathematics
1 answer:
Dimas [21]3 years ago
6 0
Alright, so the population of the herd is 220 in 2012. This means that when it decreased by 10 percent in 2014, 10 percent of the population is taken away. To find 10 percent of the population, we simply multiply 220 by 0.1 due to that to get a percentage as a decimal, we simply divide the percentage amount by 100. In addition, as the elk population in 2012 represents 100% of the elk population that we’re starting with (100%=1, or the whole thing), 10% subtracted from 100% is 90% of the population, or 220*0.9 as the population in 2013. To get the population in 2014, we have to multiply the population in 2013 by 0.9 similar to how we got from 2012 to 2013. This means we multiply (220*0.9)*0.9=178.2, which rounds down to 178 as the next number, 2, is less than 5. If that 2 were to be 5 or higher, we would round up to 179.

Feel free to ask further questions!
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Answer:

30.80

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motikmotik

Answer:

There is no statistical evidence at 1% level to accept that    the mean net contents exceeds 12 oz.

Step-by-step explanation:

Given that a random sample of ten containers is selected, and the net contents (oz) are as follows: 12.03, 12.01, 12.04, 12.02, 12.05, 11.98, 11.96, 12.02, 12.05, and 11.99.

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(Right tailed test)

Mean difference /std error = test statistic

\frac{11.015-12}{\frac{3.157}{\sqrt{10} } } \\=-0.99

p value =0.174

Since p >0.01, our alpha, fail to reject H0

Conclusion:

There is no statistical evidence at 1% level to accept that    the mean net contents exceeds 12 oz.

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3 years ago
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