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kogti [31]
3 years ago
10

Solve for Help me please

Mathematics
1 answer:
Delvig [45]3 years ago
3 0

Answer:  The first one: 2 square roots of 3

Step-by-step explanation:

4/2 would give you the base= 2

2x the square root of 3 would give you the height, or altitude.

2 square roots of 3

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Show that the equation x^3 + x -3 =0 has a solution between 1 and 2. That is the only information given
valentina_108 [34]

Answer:

Step-by-step explanation:

Given that:

f(x) = x^3 + x - 3 = 0

Since the given function is equal to zero, then the function :

f(x) = x^3 + x - 3

where;

x = 1 and

x = 2

f(x) = (1)^3 + (1) - 3 \\  \\ f(x) = 1 + 1 - 3 \\ \\f(x) = -1 < 0

f(2) =  x^3 + x - 3 \\ \\f(2) = (2)^3 + 3 - 3  \\ \\f(2) = 8 + 3 - 3  \\ \\f(2) = 11 - 3 \\ \\f(2) = 8 > 0 \\ \\

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8 0
3 years ago
Find the amount of $8000 for 3 years,compounded annually at 5% per annum. Also ,find the compound interest
Triss [41]

Answer:

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$1261

Step-by-step explanation:

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Interest rate: 5% PA compounded annually

Time: 3 years

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3 0
3 years ago
How to calculate square root?
OLEGan [10]
To calculate the square root, you can either use the √symbol on a calculator or you can manually find it using Prime Factorization. For non-perfect squares, Prime Factorization is the way to go. 
 
The first two steps work for solving large perfect squares as well.

1. Divide your number into perfect square factors.

2. Take the square roots of your perfect square factors. 

3. If your number doesn't factor perfectly, reduce your answer to simplest terms. 

4. If needed, estimate. In some cases if you have memorized some of the square roots, you can estimate where the number would be. 
ie.  \sqrt{63}       you know that 7^2 =49 and 8^2 = 64,  so you can estimate that the \sqrt{63} would be between 7 and 8 but closer to 8.

5. <span>Alternatively, reduce your number to its lowest common factors as your first step.</span><span> Finding perfect square factors isn't necessary if you can easily determine a number's prime factors (factors that are also prime numbers).
ie.  </span>\sqrt{45}
 =  \sqrt{9*5}
 = \sqrt{3*3*5}
 =   3 \sqrt{5}

Hope this helped!!!
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In the Pacific, Allied forces began to take Japanese territory by _[blank].
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