Answer= x³+4x²+16x+64

Expand the following:(x + 4 i) (x - 4 i) (x + 4)
(x - 4 i) (x + 4) = (x) (x) + (x) (4) + (-4 i) (x) + (-4 i) (4) = x^2 + 4 x - 4 i x - 16 i = -16 i + (4 - 4 i) x + x^2:
-16 i + (-4 i + 4) x + x^2 (4 i + x)
| | | | x | + | 4 i
| | x^2 | + | (4 - 4 i) x | - | 16 i
| | | | (-16 i) x | + | 64
| | (4 - 4 i) x^2 | + | (16 + 16 i) x | + | 0
x^3 | + | (4 i) x^2 | + | 0 | + | 0
x^3 | + | 4 x^2 | + | 16 x | + | 64:
Answer: x^3 + 4 x^2 + 16 x + 64

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The following are the temperatures of 10 days in winter in °C. − 3 , 0 , 10 , 2 , 8 , − 5 , − 1 , 9 , 2 , − 3 Work out the mean

marissa [1.9K]

The mean temperature of the given data − 3 , 0 , 10 , 2 , 8 , − 5 , − 1 , 9 , 2 , − 3 is 1.9

mean= 1.9

The mean, or average, is calculated by adding up the data and dividing by total number of data.

Given data: − 3 , 0 , 10 , 2 , 8 , − 5 , − 1 , 9 , 2 , − 3

Now, mean = $\frac{sum \;of\; observation}{Total \;number \;of \;observation}$