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2 years ago

How many square feet of outdoor carpet will we need for this hole?

Mathematics

1 answer:

Gwar [14]2 years ago

5 0

Answer: 66 sq ft

Step-by-step explanation:

Break up the shape into three separate shapes

8 * 3 = 24 for the rectangle

There are 2 triangles

The formula for the area of a triangle is 1/2(b)(h)

1 of the triangles has a base of 4 and height of 12

1/2(4)(12) = 24

The other triangle has a base of 3 and height of 12

1/2(3)(12) = 18

24 + 24+ 18 = 66

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Find the lateral area of the cone in terms of π.

Andreyy89

Answer:

$15\pi\ cm^{2}$

Step-by-step explanation:

we know that

The lateral area of the cone is equal to

$LA=\pi rl$

where

r is the radius of the base

l is the slant height

we have

$r=3\ cm$

Applying the Pythagoras Theorem find the slant height

$l^{2}=3^{2} +4^{2}\\ \\l^{2}=25\\ \\l=5\ cm$

substitute in the formula

$LA=\pi (3)(5)=15\pi\ cm^{2}$

8 0

2 years ago

Need help asap pls :)

pogonyaev

Answer:

See explanation below.

Step-by-step explanation:

First I'm going to find angle 2. Angle two plus 55 is equal to 115. 180-115=65. 65-55=10 Angle 2 = 10

Next, we can find angle 3. 55+10=65. 180-65=115. Angle 3 = 115

Angle 2 is equal to angle 5, angle 3 is equal to angle 6, and angle 4 is equal to 55.

Angle 5 = 10

Angle 4 = 55

Angle 6 = 115

Now we can find angle 8. 180-115=65. Angle 8 = 65

Angle 11 = 65

Angle 12 = 115

10+115=125 Angle 10 = 125

180-125 = 55 Angle 9 = 55

Angle 14 = 55

Angle 13 = 125

7 0

2 years ago

Read 2 more answers

What is the answer to 7(6x-4)+2x

amm1812

5 0

2 years ago

Read 2 more answers

Explain how you know 7(2 - 3n) and (2 - 3n) x 7 are equivalent expressions.

iogann1982 [59]

Answer:

When you distribute the 7 to each set you get 14-21n and 14-21n

Step-by-step explanation:

5 0

2 years ago

Y= x^2 -5 solve for x

dexar [7]

$Y= x^2 -5$

We need to solve for x, we need to get x alone

$Y= x^2 -5$

Lets start by removing -5

Add 5 on both sides

$y + 5= x^2 -5 + 5$

$y + 5= x^2$

Now to isolate x , we need to remove the square from x

To remove square , take square root on both sides

$+-\sqrt{y+5} = \sqrt{x^2}$

square and square root will get cancelled

$+-\sqrt{y+5} = x$

So $x = +\sqrt{y+5}$ and $x = -\sqrt{y+5}$

7 0

2 years ago