If you mean the m^3=105, then m^6 will be
![( \sqrt[3]{105}) ^6](https://tex.z-dn.net/?f=%28%20%5Csqrt%5B3%5D%7B105%7D%29%20%5E6)
which is 105^2 which is
11025
Answer:
Exact form: -√19
Decimal form: −4.35889894...
Answer:
The area that she painted = 896 mm^2
Step-by-step explanation:
Given:
The given figure is a pyramid with square base.
Here we need to find the surface area of the figure that need to be painted.
Surface area of a square pyramid = (S×S) + 2×S×L square.units
Where, S = side of the base L = slant height of the pyramid.
Now we have to plug in the given values.
Here S = 14, L =25
Plug in these values into the formula
= (14*14) + 2*14*25
= 196 + 700
= 896 mm^2
The area that she painted = 896 mm^2
Hope this will helpful.
Thank you.
4x=-3y+17 becomes 4x+3y=17
4x+3y=17
3x-4y=-6
alrighty
elimination
muliply first equation by 4 and 2nd by 3 and add them
16x+12y=68
9x-12y=-18
add them
25x+0y=50
25x=50
idivide both sides by 25
x=2
sub back
3x-4y=-6
3(2)-4y=-6
6-4y=-6
-4y=-12
y=3
(x,y)
(2,3)
