Solve: -6____=-8 ; what goes on the blank spot?

1 answer:

7 0

There are at least two different things that could go in
the blank spot and make the equation a true statement.

It could be " - 2 " .

It could be " · 4/3 " .

It could be " + 2 cos(π) "

etc.

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PLSSS HELP IF YOU TURLY KNOW THISS

geniusboy [140]

Answer:

Step-by-step explanation:

$\frac{4}{5} + \frac{2}{5} = \frac{6}{5} \\Simple make it improper, resulting in answer A$

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2 years ago

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max2010maxim [7]

A logical conclusion would say “Kelly is 15 minutes late to school.”

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3 years ago

Simplify 3(9y - 2) WILL GIVE BRAINLIST IF FULLY EXAMPLED HELP!

Musya8 [376]

Answer:

27y - 6

Step-by-step explanation:

3(9y - 2) Multiply 3 times each term in the parentheses

3 * 9y = 27y

3 * -2 = -6

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2 years ago

Read 2 more answers

(a) Use the power series expansions for ex, sin x, cos x, and geometric series to find the first three nonzero terms in the powe

Fofino [41]

Answer:

a) $\mathbf{4 + \dfrac{x}{1!}- \dfrac{2x^2}{2!} ...}$

b) See Below for proper explanation

Step-by-step explanation:

a) The objective here is to Use the power series expansions for ex, sin x, cos x, and geometric series to find the first three nonzero terms in the power series expansion of the given function.

The function is $e^x + 3 \ cos \ x$

The expansion is of $e^x$ is $e^x = 1 + \dfrac{x}{1!}+ \dfrac{x^2}{2!}+ \dfrac{x^3}{3!} + ...$

The expansion of cos x is $cos \ x = 1 - \dfrac{x^2}{2!}+ \dfrac{x^4}{4!}- \dfrac{x^6}{6!}+ ...$

Therefore; $e^x + 3 \ cos \ x = 1 + \dfrac{x}{1!}+ \dfrac{x^2}{2!}+ \dfrac{x^3}{3!} + ... 3[1 - \dfrac{x^2}{2!}+ \dfrac{x^4}{4!}- \dfrac{x^6}{6!}+ ...]$