Answer:
<h3>Figure 1</h3>
- Perimeter of base = 5 + 5 + 8 = 18 ft
- Base area = 1/2(8)(3) = 12 ft²
<u>Surface area:</u>
- S = 18*7 + 2*12 = 150 ft²
<h3>Figure 2</h3>
<u>Surface area of cube:</u>
- S = 6a² = 6(2.5)² = 37.5 m²
<u>Surface area of prism:</u>
- S = 2(11 + 9)(7) = 280 m²
<u>Overlapping area:</u>
<u>Surface area of composite figure:</u>
- S = 280 + 37.5 - 2(6.25) = 305 m²
Answer:
the height after 2 seconds will be 128 feet
Step-by-step explanation:
Data provided in the question:
Initial velocity = 96 feet per second
The function of height of falling debris above the ground is given as:
h(t) = 96t - 16t²
A) To find height after time t = 2 seconds
substituting the value of time in the above function, we get
h(t) = 96 × 2 - 16 × 2²
or
h(t) = 192 - 16 × 4
or
h(t) = 192 - 64
or
h(t) = 128 feet
Hence,
the height after 2 seconds will be 128 feet
The radius of tire is larger than radius of wheel by 5 inch
Step-by-step explanation:
We know that circumference of the circle is 2πr where “r” is the radius of the circle
Circumference refers to the dimension of the periphery of the circle. Since tires are put on the periphery of the wheel hence, we considered the circumferential aspect of the wheel.
Given-
Circumference of tires= 28π inches
2πr= 28π cancelling the common term “π” both sides
r (radius of the tires) = 14 inches
Circumference of the wheel rims= 18π
2πr= 18π cancelling the common term “π” both sides
r (radius of the tires) = 9 inches
Difference between the radius= 14-9= 5 inches
Hence, the difference between the radius of tires and the radius of the wheels is 5 inches
Answer:
b
Step-by-step explanation:
Answer:
A square
Step-by-step explanation:
Rectangles have 4 parallel sides and rhombi have equal side lengths. A square has same side lengths and 4 parallel sides
