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bogdanovich [222]
3 years ago
8

G(x)=5x^2+10 compare the graph of the function with the graph of f(x)=x^2

Mathematics
1 answer:
dybincka [34]3 years ago
4 0
Wow you are great !!
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Find the surface area of the square pyramid shown below. (Measurements in picture)
Sloan [31]

Given:

Side length of base = 8

Slant height = 6

To find:

The surface area of the square pyramid.

Solution:

Surface area:

$SA=A+\frac{1}{2} p s

where A is the area of base

p is the perimeter of base

s is the slant height

Area of base (A) = 8 × 8

                           = 64

Perimeter of base(P) = 4 × 8

                                  = 32

Substitute these in the formula:

$SA=64+\frac{1}{2} \times 32 \times 6

$SA=64+96

$SA=160

The surface area of the square pyramid is 160 unit².

8 0
3 years ago
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What’s the correct graph ?
maks197457 [2]

Answer:

The correct graph is graph E.

Step-by-step explanation:

We can tell this because we know the graph must stay below 3. So any graph over 3 gets thrown out. We also know that it must not go further down than -3. This is because any number over -3 as an input, when taking an absolute value, would be greater than 3.

Graph E shows numbers that are all less than 3 and greater than -3.

8 0
3 years ago
Simply the fraction 16/24
stepladder [879]
2/3 because you can divide the top and bottom by 8
5 0
3 years ago
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Use complete sentences to describe why Set A = { X | X is an even whole number between 0 and 2} = ∅
RoseWind [281]

Consider the Set A = {X | X is an even whole number between 0 and 2 } = \Phi.

Since, whole numbers are the set of numbers starting from zero upto infinity.

Even numbers are the numbers which are exactly divisible by '2'.

So, we have to find the even whole number between 0 and 2.

Since, only '1' is a whole number between 0 and 2 which is not an even number as '1' is not divisible by '2'.

Therefore, there is no even whole number between 0 and 2.

So, this set is empty.

Therefore, A = { X | X is an even whole number between 0 and 2} =  \Phi

3 0
3 years ago
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What's the cube root of 2744000
Paraphin [41]
The cube root of 2744000 is 140
4 0
4 years ago
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