Convert to stand both expressions to standard form:
416.1 + 4,560
Add:
4,976.1
198 feet..........1 meter
<span>------------- X-------------- </span>
<span>1 second.......3.3 feet </span>
<span>198 </span>
<span>----- meters per second </span>
<span>3.3 </span>
<span>60 meters per second.......ANSWER </span>
<span>60 m/sec X 15 sec = 900 feet.......ANSWER </span>
<span>If you have questions on this or any other math problem feel free </span>
<span>to let me know how to contact you.......Read Below....... </span>
<span>I tutor free online since moving to France from Florida in June 2011. </span>
<span>I still tutor by skype to students in Florida and starting to gain more world-wide. </span>
<span>Hope this is most helpful and you will continue to allow me to tutor you. </span>
<span>If you dont fully understand or have a question PLEASE let me know </span>
<span>how to contact you so you can then contact me directly with any math questions. </span>
<span>If you need me for future tutoring I am not allowed to give out my </span>
<span>info but what you tell me on ***how to contact you*** is up to you </span>
<span>Been a pleasure to serve you Please call again </span>
<span>Robert Jones.............f </span>
<span>"Teacher/Tutor of Fine Students" </span>
<span>A PRESENT FOR YOU </span>
<span>Ask someone to write a number, say a five-digit number. </span>
<span>(Can be a 2-digit.....3-digit.....4-digit....ect..... </span>
<span>Suppose the number written is </span>
<span>57836 </span>
<span>Now, without showing the asker, you write a number on </span>
<span>a sheet of paper and keep it folded. You have to write the </span>
<span>number by subtracting 2 from the above number and </span>
<span>adding 2 in front which will be.... </span>
<span>257834 </span>
<span>Next, ask the person to write another five-digit number </span>
<span>below his original number. Suppose he writes 37589. </span>
<span>So you now have... </span>
<span>57836 </span>
<span>37589 </span>
<span>Now you write a five-digit number below it in such a </span>
<span>way that each digit is 9 minus digit above. You now have... </span>
<span>57836 </span>
<span>37589 </span>
<span>62410 </span>
<span>Ask the person to add one more 5-digit number. If he </span>
<span>adds 54732, you add below it 45267. Note that you decided </span>
<span>the number by subtracting each of his digit from 9. </span>
<span>Thus, you now have..... </span>
<span>57836 </span>
<span>37589 </span>
<span>62410 </span>
<span>54732 </span>
<span>45267 </span>
<span>Next, ask him to add all the number and he gets 257834 </span>
<span>Show him the number which you had written as an answer </span>
<span>to this addition earlier in the folded paper and surprise him.</span>
Answer:
27
Step-by-step explanation:
angle adjacent to 163 = 27
x=27 by alternate angles equal principle.
Answer:
Step-by-step explanation:
The radical 
can be simplified by breaking it down into factors and removing the perfect squares from inside the radical.
25 is a perfect square and is 5 outside the radical.
is a perfect square and is x outside the radical.
is a perfect square and is 
outside the radical.
Answer:
see explanation
Step-by-step explanation:
To multiply the vector by a scalar, multiply each of the elements by the scalar.
To add 3 vectors add the corresponding elements of each vector
2a + 3b + 4c
= 2![\left[\begin{array}{ccc}2\\3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%5C%5C3%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ 3![\left[\begin{array}{ccc}-4\\1\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-4%5C%5C1%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ 4![\left[\begin{array}{ccc}3\\2\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%5C%5C2%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}4\\6\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%5C%5C6%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ ![\left[\begin{array}{ccc}-12\\3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-12%5C%5C3%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ ![\left[\begin{array}{ccc}12\\8\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%5C%5C8%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}4-12+12\\6+3+8\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4-12%2B12%5C%5C6%2B3%2B8%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}4\\17\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%5C%5C17%5C%5C%5Cend%7Barray%7D%5Cright%5D)
