The answer and steps for this question
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Answer:
Jogging 6th time.
Step-by-step explanation:
We have been given that Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16 mile.
We can see that the distance Vicki covers each time forms a arithmetic sequence, where 1st term is 3/16.
We know that an arithmetic sequence is in form , where,
= nth term of sequence,
= 1st term of sequence,
n = Number of terms in sequence,
d = Common difference.
Let us find common difference of our given sequence as:
Since Vicki needs to cover more than 1 mile, so we nth term of sequence should be greater than 1.
Let us solve for n.
We can also write next terms of our sequence as:
Therefore, Vicki will run more than 1 mile when she is jogging for 6th time.
Answer:
Step-by-step explanation:
a)
Substitute limits to get
=
Thus converges.
b) 10th partial sum =
=
c) Z [infinity] n+1 1 /x ^4 dx ≤ s − sn ≤ Z [infinity] n 1 /x^ 4 dx, (1)
where s is the sum of P[infinity] n=1 1/n4 and sn is the nth partial sum of P[infinity] n=1 1/n4 .
(question is not clear)