X-intercepts are points where the graph intersects the x-axis, i.e. when y=0.
Substitute y=0 and solve for x:
y=x^2-3x+2
0=x^2-3x+2
0=(x-2)(x-1)
By the zero product property, we deduce x-2=0 or x-1=0, i.e. x=1 or x=2.
Answer: 31 and 1/9
Step-by-step explanation:
d =29, for g=16,h=9
replace values of each number in equati/on:
d+g/h=29+19/9=(9*29+19)/9=( 261+19)/9=280/9= 31 and 1/9
Given that

, then

The slope of a tangent line in the polar coordinate is given by:

Thus, we have:

Part A:
For horizontal tangent lines, m = 0.
Thus, we have:

Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are horizontal are:
</span><span>θ = 0
</span>θ = <span>2.02875783811043
</span>
θ = <span>4.91318043943488
Part B:
For vertical tangent lines,

Thus, we have:

</span>Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are vertical are:
</span>θ = <span>4.91718592528713</span>
Answer:
x=1 y =15
Step-by-step explanation:
hopefully correct
-5x-2y=13 (i)
3x-y=12
-y=12-3x
y=-12+3x (ii)
substitute ii into i
-5x-2(-12+3x)=13
-5x +24-6x=13
-11x=-11
x=1
substitute x into ii
y=-12+3(1)
y=15
.
. . x=1 and y =15
Answer:
a
Step-by-step explanation: