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Orlov [11]
3 years ago
14

The Mathalot company makes and sells textbooks. They have one linear function thst represents the cost of producing textbooks an

d another linear function that models how much income they can get from those textbooks. Describe the key features that would determine if these linear functions ever intercepted.
Mathematics
2 answers:
OverLord2011 [107]3 years ago
3 0

It's only possible for the two lines to intercept isif they have different slopes.

When two lines have the same slope they would be parallel and never intercept.

If the lines have different slopes, they would  eventually intercept.

Levart [38]3 years ago
3 0

Answer:

Two lines only can intercept if they have different slopes, if they have the same slope, the lines are parallel and they never intercept.

So if the cost of producing a book is different than the price of selling the book, the lines will intercept at some point.

Where the equations can be:

lose = A*x + b

win = C*x + d

where x is the number of books, A and C are the slopes, b and d are constants. Those two lines only will intercept if A is bigger than C, the intercept will be for x different than zero only when b is different than d

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A sample of 900900 computer chips revealed that 49%49% of the chips do not fail in the first 10001000 hours of their use. The co
dedylja [7]

Answer:

The proportion of chips that do not fail in the first 1000 hours of their use is 52%.

Step-by-step explanation:

The claim made by the company is that 52% of the chips do not fail in the first 1000 hours of their use.

A quality control manager wants to test the claim.

A one-proportion <em>z</em>-test can be used to determine whether the proportion of chips do not fail in the first 1000 hours of their use is 52% or not.

The hypothesis can be defined as:

<em>H₀</em>: The proportion of chips do not fail in the first 1000 hours of their use is 52%, i.e. <em>p</em> = 0.52.

<em>Hₐ</em>: The proportion of chips do not fail in the first 1000 hours of their use is different from 52%, i.e. <em>p</em> ≠ 0.52.

The information provided is:

\hat p=0.49\\n=900\\\alpha =0.02

The test statistic value is:

z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}=\frac{0.49-0.52}{\sqrt{\frac{0.52(1-0.52)}{900}}}=-1.80

The test statistic value is -1.80.

Decision rule:

If the <em>p-</em>value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

Compute the <em>p</em>-value as follows:

p-value=2\times P(Z

*Use a <em>z</em>-table.

The <em>p</em>-value = 0.07186 > <em>α</em> = 0.02.

The null hypothesis was failed to be rejected at 2% level of significance.

<u>Conclusion</u>:

The proportion of chips that do not fail in the first 1000 hours of their use is 52%.

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We know that:

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Step-by-step explanation:

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