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Fiesta28 [93]
2 years ago
10

What is the image of (0,4) after a dilation by a scale factor of 1/2 centered at the origin

Mathematics
1 answer:
Firlakuza [10]2 years ago
5 0

Answer:

(0,2)

Step-by-step explanation:

Multiply the x and y by 1/2

0*1/2=0

4*1/2=2

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Isabel works for 6 hours preparing for the art fair. She spends 3 hours on a sculpture and then paints 27 picture frames. How mu
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Answer: 3?

Step-by-step explanation: 3?

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Which relationship describes angles 1 and 2?
malfutka [58]

Answer:

vertical angles

Step-by-step explanation:

When two lines intersect at a single point, they form 4 angles. Two angles that are not adjacent are vertical angles. With an intersection of two lines art a single point, there are two pairs of vertical angles. Angles 1 and 2 are vertical angles.

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2 years ago
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Use the Change of Base Formula to evaluate log5 92. Then convert log5 92 to a logarithm in base 3. Round to the nearest thousand
ANTONII [103]
I was thinking that the answer  could be 

2.810; log3 21.903
         
            OR


<span> 2.810; log3 55.2 </span>

So,<span> log5 of 92 is between 2.5 and 3  Correct answer is A</span>

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3 years ago
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The gym is located 3 blocks to the left of the hospital (3,6) What are the coordinate point
Romashka-Z-Leto [24]
(6,6) this is the answer. add 3 to the x value
8 0
2 years ago
Read 2 more answers
I need help ASAP! Can anyone please check my work?
STALIN [3.7K]

A = event the person got the class they wanted

B = event the person is on the honor roll

P(A) = (number who got the class they wanted)/(number total)

P(A) = 379/500

P(A) = 0.758

There's a 75.8% chance someone will get the class they want

Let's see if being on the honor roll changes the probability we just found

So we want to compute P(A | B). If it is equal to P(A), then being on the honor roll does not change P(A).

---------------

A and B = someone got the class they want and they're on the honor roll

P(A and B) = 64/500

P(A and B) = 0.128

P(B) = 144/500

P(B) = 0.288

P(A | B) = P(A and B)/P(B)

P(A | B) = 0.128/0.288

P(A | B) = 0.44 approximately

This is what you have shown in your steps. This means if we know the person is on the honor roll, then they have a 44% chance of getting the class they want.

Those on the honor roll are at a disadvantage to getting their requested class. Perhaps the thinking is that the honor roll students can handle harder or less popular teachers.

Regardless of motivations, being on the honor roll changes the probability of getting the class you want. So Alex is correct in thinking the honor roll students have a disadvantage. Everything would be fair if P(A | B) = P(A) showing that events A and B are independent. That is not the case here so the events are linked somehow.

8 0
3 years ago
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