1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Fiesta28 [93]
2 years ago
10

What is the image of (0,4) after a dilation by a scale factor of 1/2 centered at the origin

Mathematics
1 answer:
Firlakuza [10]2 years ago
5 0

Answer:

(0,2)

Step-by-step explanation:

Multiply the x and y by 1/2

0*1/2=0

4*1/2=2

You might be interested in
you choose at random from the letters a,b,c and d and you roll a number cube once. what are the chances that you get an a and 5?
Keith_Richards [23]
1/24 or 4%

There is a total of 24 outcomes
4 letters • 6 numbers = 24 possible outcomes
There are 6 different outcomes when it comes to each letter.
(a1, a2, b1, b2 etc)
so getting a5 is a 1/24 chance because there 24 outcomes and only one of them is a5
7 0
3 years ago
It is estimated that approximately 8.23% Americans are afflicted with diabetes. Suppose that a certain diagnostic evaluation for
allsm [11]

The probabilities in this problem are given as follows:

a) False positive: 0.0321 = 3.21%.

b) Diagnosed as not having diabetes: 0.8872 = 88.72%.

c) Actually has diabetes, if diagnosed as not having: 0.0019 = 0.19%.

<h3>What is Conditional Probability?</h3>

Conditional probability is the probability of one event happening, considering a previous event. The formula is given as follows:

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which the parameters are described as follows:

  • P(B|A) is the probability of event B happening, given that event A happened.
  • P(A \cap B) is the probability of both events A and B happening.
  • P(A) is the probability of event A happening.

For item a, we have that:

  • 100 - 8.23 = 91.77% of the people do not have diabetes.
  • Of those, 3.5% are diagnosed with diabetes.

Hence the probability of a false positive is given as follows:

p = 0.9177 x 0.035 = 0.0321 = 3.21%.

For item b, the percentage of people who is not diagnosed as having diabetes is divided as:

  • 96.5% of 91.77% (do not have diabetes).
  • 2% of 8.23% (have diabetes).

Hence the probability is:

P(A) = 0.965 x 0.9177 + 0.02 x 0.0823 = 0.8872 = 88.72%.

For item c, we find the conditional probability, as follows:

P(A \cap B) = 0.02 \times 0.0823 = 0.001646

Then:

P(B|A) = 0.001646/0.8872 = 0.0019 = 0.19%.

More can be learned about probabilities at brainly.com/question/14398287

#SPJ1

7 0
1 year ago
What is the vale of ■ in this equation?<br>7×9=(7×10)-(7×■)
aliina [53]
The answer is 1 because 7*9 is 63
7*10=70 70-7=63
5 0
3 years ago
Read 2 more answers
What if the GCF of 18 and 54?
Viktor [21]

Answer:

18 is the GCF for 18 and 54

8 0
2 years ago
Read 2 more answers
-6/7 × (-3/8) answer?/
Mumz [18]

Answer:

Step-by-step explanation:

0.32142857142

3 0
2 years ago
Read 2 more answers
Other questions:
  • Priya spent 1/2 of the day hiking. she was lost 5/6 of the time that she was hiking.
    12·1 answer
  • you are permitted a 50-pound check bag for free on your flight to Florida your bag weighs 32 pounds. write and solve an inequali
    8·1 answer
  • A probability close to 1/2 indicates a chance event is ________ to occur
    5·1 answer
  • How to estamite 787÷2
    13·2 answers
  • Factoring polynomials multiply 2xy(x^2-xy^3)​
    11·1 answer
  • Which table shows a relationship between the values of x and y that represents a linear function?
    9·1 answer
  • which of the following is the estimated sum of sixty-five and one-hundred-fifty using compatible numbers? A. 200 B. 210 C. 220 D
    11·2 answers
  • Sara threw 6 darts at this dartboard, and they all hit the target. Which of the following numbers could have been her score: 4,2
    5·1 answer
  • A mother saved 7/8 pie for dinner son ate 1/2 how much is left
    7·1 answer
  • 17, 18, 22, 31, 47, ?
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!