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3 years ago

10

What is the image of (0,4) after a dilation by a scale factor of 1/2 centered at the origin

1 answer:

Firlakuza [10]3 years ago

5 0

Answer:

(0,2)

Step-by-step explanation:

Multiply the x and y by 1/2

0*1/2=0

4*1/2=2

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True or False: A sample taken from a normally distributed population will also be normally distributed.

ElenaW [278]

The <em><u>correct answer</u></em> is:

False.

Explanation:

We cannot be sure that all samples from a normal distribution will also be normally distributed.

The Central Limit Theorem states that the sampling distribution of the sample means approaches a normal distribution as the sample size gets larger, especially for sample sizes over 30. Basically as you take more samples from a given distribution, especially large samples, the graph of the sample means will look more like a normal distribution.

However, this does not state that all samples of a normal distribution will also be normal.

6 0

4 years ago

Read 2 more answers

Which results only in a horizontal compression of Y =

Dmitry_Shevchenko [17]

Answer:

y=1/6x

Step-by-step explanation:

7 0

3 years ago

The Student Monitor surveys 1200 undergraduates from 100 colleges semiannually to understand trends among college students. Rece

nlexa [21]

Answer:

A sample size of 385 is needed.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.025 = 0.975$ , so Z = 1.96.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

You feel that a reasonable estimate of the standard deviation is 10.0 hours.

This means that $\sigma = 10$

What sample size is needed so that the expected margin of error of your estimate is not larger than one hour for 95% confidence?

A sample size of n is needed. n is found when M = 1. So

$M = z\frac{\sigma}{\sqrt{n}}$

$1 = 1.96\frac{10}{\sqrt{n}}$

$\sqrt{n} = 1.96*10$

$(\sqrt{n})^2 = (1.96*10)^2$

$n = 384.16$

Rounding up:

A sample size of 385 is needed.

7 0

3 years ago

Write the expression 12 x 4^2 in words

lawyer [7]

Answer and Step-by-step explanation:

Twelve times four squared.

This is how you would write the expression in word format.

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

7 0

3 years ago

Stewart School has 178 computers. Grade 3 has 58 computers and flgrade 4 has 57 computers. What equations can be used to find ho

Ilya [14]

Answer: $x=58+57=115$

$y=178-115=63$

Step-by-step explanation:

Let x be the number of computers Grade 3 and grade 4 has and y be the numbers of computers the rest of school has.

Then, x= Grade 3 computers +Grade 4 computers.

$\Rightarrow\ x=58+57=115$

And y = Total computers - x

$\Rightarrow\ y=178-115=63$

Therefore, The equations can be used to find how many computers the rest of the school has.

$x=58+57=115$

$y=178-115=63$

7 0

4 years ago