Answer: N >/= 7 bits
Minimum of 7 bits
Step-by-step explanation:
The minimum binary bits needed to represent 65 can be derived by converting 65 to binary numbers and counting the number of binary digits.
See conversation in the attachment.
65 = 1000001₂
65 = 7 bits :( 0 to 2^7 -1)
The number of binary digits is 7
N >/= 7 bits
Since it is a parallelogram cente at point T,
then the measure of PT is equal to the measure of TR. And the measure of QT is
equal to the measure of TS.
PT = TR
a + 4 = 2a
4 = 2a -a
a = 4
PT = TR = 8 units
QT = TS
b = 2b -3
3 = 2b – b
b = 3
<span>QT = TS = 3 units</span>
Hello from MrBillDoesMath!
Answer: The other side has a length of 8
Discussion:
Area of a rectangle = l * w ( length times width). In our case
Area = 144 = l * w = 18 * w =>
18 w = 144 =>
w = 144/18 = 8
Thank you,
MrB
Step-by-step explanation:
Given,
Perimeter of the rectangle = 200cm
Breadth of the rectangle = 10 cm
Therefore, by the problem
=> 2(l+b) = 200cm
=> 2(l + 10) = 200cm

=> l + 10 = 100
=> l = 100 - 10
=> l = 90
<u>Hence, required length othe rectangle is 90 cm (Ans)</u>