Let's imagine we enclosed the entire shape in a 15 inch wide, 21 inch tall rectangle, area 315 sq inches.
From that rectangle we have to take away the 3x6 bottom left corner, and a strip 21-6=15 inches long and 3 inches wide on the right.
A = 15×21 - 3×6 - 3×15 = 315 - 63 = 252 sq in
Answer: D. 252 inches squared, last choice
Answer:
s = 22.5 m
Step-by-step explanation:
the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.
v (t) = 25 - 5 t
at t = 0 , v = 20 m/s
Let the distance is s.

Let at t = t, the v = 20
So,
20 = 25 - 5 t
t = 1 s
So, s = 25 x 1 - 2.5 x 1 = 22.5 m
C is 50 cents because 2 dollars divided by 4 is 50
Answer:
Step-by-step explanation:
2200(1+0.0225/12) raised to the power of 12(4)
2200(1.001875) raised to the power of 12(4)
2204.125 raised to the power of 12(4)
2.98771099E160
or 2.98771099 multiplied by 10 to the 160th power