Question

Someone please help me i am so bad with point slope stuff

Answer 1

Answer:

1.) y = -6

2.) y = 5/3x - 7

3.) y = 5

4.) y = -3x + 1

5.) x = -3

Step-by-step explanation:

So the equation you want to use is this:   $\frac{y2-y1}{x2-x1}$

1.) Plug in

$\frac{-6 - (-6)}{6 - 2} \\\\\frac{0}{4} = 0$

This line is zero slope to find the y-intercept get one of you points and plug them and the slope into this equation y = mx+ b. We will use (2,-6)

-6 = 0(2) + b (b represents y-intercept) (0*2=0)

-6 = b

So the equation is y = -6

2.) Do the same thing.

$\frac{3-8}{6-9} \\\\\frac{-5}{-3} =\frac{5}{3}$

It's positive because when you divide a negative by a negative you get a positive. Plug in a point (6, 3) y = mx + b (b represents y-intercept)

3 = 5/3(6) + b (5/3*6 = 10)

3 = 10 + b (subtract 10 on both sides)

-7 = b

y = 5/3x - 7

3.) For this one you are just going to point slope form. y - y1 = m(x - x1)

Plug in

y - 5 = 0(x - (-8))

y - 5 = 0 (add 5 to both sides)

y = 5

4.) Do $\frac{y2 - y1}{x2 - x1}$ for this one

Plug in

$\frac{-5 - 7}{2 - (-2)} \\\\\frac{-12}{4} = -3$

So the slope is -3. Plug into y = mx + b with the point (2, -5)

-5 = -3(2) + b (b represents y-intercept)

-5 = -6 + b (add 6 to both sides)

1 = b

The equation is y = -3x + 1

5.) Do the same thing as #4

$\frac{-8 - (-5)}{6 - 6} \\\\\frac{-3}{0}$

This slope is undefined

Since you can't divide by 0 the equation would be

x = -3

Hope this helps ya!!