Answer:
A=πr(r+h2+r2)
Step-by-step explanation:
literally just search it up
Since you know Z = 2, you can plug it into:
Y = 5 · Z²
Y = 5 · (2)²
Y = 5 · 4
Y = 20
Now that you know Y = 20, you can plug it into:
X = 2 + 5Y
X = 2 + 5(20)
X = 2 + 100
X = 102
Now that you have X, plug it into "2+2X=?"
2 + 2x = ?
2 + 2(102) = ?
2 + 204 = ?
206 = ?
Answer:
There will be a 100 branches on tree in approximately 12 years.
Step-by-step explanation:
Concluding part of the question
In how many years will the number of branches be 100?
Solution
N(t)=38 × (9/5) ^ t/7.3
N(t)=38 × (1.8) ^ t/7.3
a) N = 100, t = ?
100 = 38 × (1.8) ^ (t/7.3)
(100/38) = (1.8) ^ (t/7.3)
2.632 = (1.8) ^ (t/7.3)
Taking the natural logarithms of both sides,
In 2.632 = In [(1.8) ^ (t/7.3)]
0.9676 = (t/7.3) × In 1.8
0.9676 = (t/7.3) × 0.5878
t = (0.9676 × 7.3) ÷ 0.5878
t = 12.02 years = 12 years.
Hope this Helps!!!
Answer:
1/6 = 0.1667 = 16.67%
Step-by-step explanation:
If there are 24 students in the class and 7 of them take neither courses, we have 17 students that take one or both courses.
To find the students that took both courses, we can use the formula:
N(Spanish or French) = N(Spanish) + N(French) - N(Spanish and French)
17 = 13 + 12 - N(Spanish and French)
N(Spanish and French) = 8
Then, the number of students that are taking only French is:
N(only French) = N(French) - N(Spanish and French)
N(only French) = 12 - 8 = 4
So the probability of chosing a student that took only French is:
P(only French) = N(only French) / N(total)
P(only French) = 4 / 24 = 1/6