hello:) i think that AB is longer than DC but I’m not sure if it’s correct :/ anyone able to help ? thank you!

Mathematics

1 answer:

blsea [12.9K]3 years ago

5 0

<h3>Answer: You are correct. AB is longer than DC.</h3>

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Explanation:

OM and ON are not equal in length, so the chords AB and CD are not the same length. The chords would need to be equally distant from the center for the chords to be equal.

The further a chord gets from the center, the smaller the chord gets. This is because the diameter is the largest chord possible and its distance from the center is 0 units. Increase that distance and the chord will shrink until it reaches 0 units in length.

You are correct in stating that AB is longer than DC because AB is closer to the center (or that OM is smaller than ON).

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<h3>What is the percentage?</h3>

The quantity of anything is stated as though it were a fraction of a hundred. A fraction of 100 can be used to express the ratio.

The right question is

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Given data;

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Find the point P on the line y=2x that is closest to the point (20,0) .what is the least distance between pans (20,0)?

Vsevolod [243]

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so, we know that line passes through the point 20,0, and has a slope of -1/2

if we plug that in the point-slope form, we get $\bf y-0=-\cfrac{1}{2}(x-20)\implies y=-\cfrac{1}{2}x+10$

now, the point that's on 2x and is also on that perpendicular line, is the closest to 20,0 from 2x, thus, is where both graphs intersect, as you can see in the graph

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not sure on the 2nd part, but sounds like, what's the distance from that point to 20,0, well, if that's the case, just use the distance equation

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ \square }}\quad ,&{{ \square }})\quad 
% (c,d)
&({{ \square }}\quad ,&{{ \square }})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}$