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3 years ago

11

Identify the pair of events as dependent or independent. An odd-numbered problem is assigned for homework, and an even-numbered

problem is picked for a test.

1 answer:

S_A_V [24]3 years ago

5 0

Hello!

As the homework and test are two separate things, selecting an odd or even number on either of them will not affect the probability of selecting an odd or even number on the other.

Therefore, this pair of events is independent.

I hope this helps!

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Problem 2.9 a runner completes the 200-meter dash with a time of 20.19 seconds. part a what was the runner's average speed in me

Elina [12.6K]

Answer:

Average speed = 9.91 m/s

Explanation :

Total distance covered by a runner = 200 m

Time taken to complete this distance = 20.19 sec

We need to find the average of runner speed in meter/sec

We use the speed, distance, time formula

$speed = \frac{distance}{time}$

speed = $\frac{200}{20.19}$

Average speed = 9.91 m/s

that's the final answer.

I hope it will help you.

8 0

3 years ago

Divide 2/8 by 9/18 . Input your answer as a reduced fraction.\

Katen [24]

$\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{\sf{\frac{2}{8}\div\frac{9}{18} }} \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf Simplify \ \frac{2}{8} \ to \ \frac{1}{4}. \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{\sf{\frac{1}{4}\div\frac{18}{9} }} \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf Use \ this \ rule: a\div \frac{b}{c}=a\times \frac{c}{b}a \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{\sf{\frac{1}{4}\times\frac{18}{9} }} \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf Use \ this \ rule: \frac{a}{b} \times \frac{c}d{}=\frac{ac}{bd}. \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{\sf{\frac{1\times18}{4\times9} \ \to \ \ Multiply }} \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{\sf{ \frac{18}{36}= }}\boxed{\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{\sf{\frac{1}{2} }} \end{gathered}$}} \end{gathered}$}$

8 0

2 years ago

Read 2 more answers

For each month of a given year except December, a worker earned the same monthly salary and donated one-tenth of that salary to

kiruha [24]

Answer:

D) 11/3

Step-by-step explanation:

Let x represent monthly salary.

We have been given that for each month of a given year except December, a worker earned the same monthly salary and donated one-tenth of that salary to charity.

Salary earned in 11 months would be $11x$ .

Money donated in 11 months would be $\frac{11x}{10}$ .

Further we are told that in December, the worker earned N times his usual monthly salary and donated one-fifth of his earnings to charity.

Salary for December would be $Nx$ .

Money donated in December would be $\frac{Nx}{5}$ .

The worker's charitable contributions totaled one-eighth of his earnings for the entire year that is $\frac{1}{8}\cdot (11x+Nx)$ .

$\frac{11x}{10}+\frac{Nx}{5}=\frac{1}{8}\cdot (11x+Nx)$

Dividing whole equation by x, we will get:

$\frac{11x}{10x}+\frac{Nx}{5x}=\frac{1}{8x}\cdot x(11+N)$

$\frac{11}{10}+\frac{N}{5}=\frac{1}{8}\cdot (11+N)$

$\frac{11}{10}+\frac{N}{5}=\frac{11}{8}+\frac{N}{8}$

Combine like terms:

$\frac{N}{5}-\frac{N}{8}=\frac{11}{8}-\frac{11}{10}$

$\frac{N}{5}*40-\frac{N}{8}*40=\frac{11}{8}*40-\frac{11}{10}*40$

$8N-5N=11*5-11*4$

$3N=55-44$

$3N=11$

$\frac{3N}{3}=\frac{11}{3}\\\\N=\frac{11}{3}$

Therefore, the value of N is 11/3 and option D is the correct choice.

4 0

3 years ago

Mel is taking her holidays. She receives $2937.50. This includes her normal pay

galina1969 [7]

17.5% leaving load
You do 0.0175 divided by the money
$2937.50
———-
0.0175

8 0

3 years ago

Mrs. O'Neill had nine times as many markers as colored pencils the total number of markers and colored pencils is 110 how many c

tamaranim1 [39]

9x+x=110

10x=110

divide 10 on both sides

x=11

11 colored pencils

99 markers

5 0

4 years ago