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KengaRu [80]
3 years ago
12

Using the tables above find the mean, median, mode, and range of the prices of Felix's and Tyler's books Felix Price ($) Number

of books 3 4 5 6 7 8 9 11 13 15 18 19 29 total 50 Tyler Price ($) Number of books 7 8 9 13 16 18 32 36 38 64 66 68 69 75 76 78 79 82 86 89 96 97 99 total 50
Mathematics
1 answer:
Mazyrski [523]3 years ago
3 0

For Felix's books, Mean = 11.3076923... , Median = 9, Mode = none and Range = 26

For Tyler's books, Mean = 56.565217... , Median = 68, Mode = none and Range = 92

Felix Price

3 4 5 6 7 8 9 11 13 15 18 19 29

Mean is just the average of all numbers. As there is total 13 numbers, so for finding the average, we will divide the Sum of all numbers by 13.

So, Mean = \frac{3+4+5+6+7+8+9+11+13+15+18+19+29}{13} = \frac{147}{13} =11.3076923...

Median is the middle value in the data set. For finding the median, first we need to rearrange the data set in numerical order, but here the data set is already in numerical order. As there is total 13 numbers, so the middle value will be the (13+1)÷2 = 7th number

3 4 5 6 7 8 9 11 13 15 18 19 29

So, the median is 9 .

The mode is the number that is repeated more often than any other in the data set, but here all the numbers in this set appear only once.

So, there is no mode.

Range is the difference between the largest and smallest values in the set. The largest is 29 and the smallest is 3.

So, the range = 29 - 3 = 26

Tyler Price

7 8 9 13 16 18 32 36 38 64 66 68 69 75 76 78 79 82 86 89 96 97 99

There are total 23 numbers.

So, the Mean = \frac{7+8+9+13+16+18+32+36+38+64+66+68+69+75+76+78+79+82+86+89+96+97+99}{23}\\ \\ =\frac{1301}{23}\\ \\ =56.565217...

The middle value will be the (23 + 1)÷ 2 = 12th number.

7 8 9 13 16 18 32 36 38 64 66 68 69 75 76 78 79 82 86 89 96 97 99

So, the median = 68

Here also all the numbers in this data set appear only once. So, there is no mode.

Largest value is 99 and smallest value is 7.

So, the range = 99 - 7 = 92

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Tresset [83]
10-3 2/5
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