47 Simplify 52 4 10 55 RE 5 421 56 127 153

Mathematics

1 answer:

miskamm [114]2 years ago

5 0

Please rephrase the question. It would be helpful if you post a picture of it. The way it is worded is confusing.

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Katie and jennifer are playing a game. katie and jennifer each started with 100 points. at the end of each turn katies points do

ella [17]

It is the fourth round and this is because in round one Katie has 200 and Jenny will have 300.In round two katie will have 400 and Jennifer will have 500.In round 3 Katie will have 600 and and jennifer will have 800.I

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2 years ago

Ruben sees 14 wheels on a total of 6 bicycles and tricycles. How many bicycles and tricycles are there?

Rina8888 [55]

4 bicycles 2 tricycles
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2 years ago

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n an orchid show, seven orchids are to be placed along one side of the greenhouse. of the orchids, we see that the number of lin

NNADVOKAT [17]

Answer:

Step-by-step explanation:

7 orchids can be lined as 7!. This means that for the first orchid of the line, you can select 7 options. When you place the first orchid, for the second option you can select among 6 since 1 orchid has already been placed. Similarly, for the 3rd orchid of the line, you have left 5 options. The sequence goes in this fashion and for 7 orchids, you have 7*6*5*4*3*2*1 possibilities. However, there is a restriction here. 3 of the orchids are white and 4 are levender. This means that it does not make a difference if we line 3 white orchids in an arbitrary order since it will seem the same from the outside. As a result, the options for lining the 7 orchids diminish. The reduction should eliminate the number of different lining within the same colors. Similar to 7! explanation above, 3 white orchids can be lined as 3! and 4 levender orchids can be lined as 4!. To eliminate these options, we divide all options by the restrictions. The result is:

$\frac{7!}{4!*3!}$ = 35. [(7*6*5*4*3*2*1/(4*3*2*1*3*2*1)]