What is the value of sin(C)?

Suppose that each time Giannis Antetokounmpo shoots a free throw, he has a 3/4 probability of success. If Giannis shoots three f

GREYUIT [131]

Answer:

84.38% probability that he succeeds on at least two of them

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either Giannis makes it, or he does not. The free throws are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

He has a 3/4 probability of success.

This means that $p = \frac{3}{4} = 0.75$

Giannis shoots three free throws

This means that $n = 3$

What is the probability that he succeeds on at least two of them

$P(X \geq 2) = P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{3,2}.(0.75)^{2}.(0.25)^{1} = 0.4219$

$P(X = 3) = C_{3,3}.(0.75)^{3}.(0.25)^{0} = 0.4219$

$P(X \geq 2) = P(X = 2) + P(X = 3) = 0.4219 + 0.4219 = 0.8438$

84.38% probability that he succeeds on at least two of them

6 0

3 years ago

The average temperature in the North Pole in the summer is 32 degrees F. The average temperature in the North Pole in the winter

wlad13 [49]

Answer:

he counted from 32 to 40 , and not to -40

Step-by-step explanation:

the difference is 72 degrees

7 0

3 years ago

The diameter of circles A,C and E are 32 cm, 24cm and 14 cm respectively

Karolina [17]

Answer:

AG = 4

AH = 21

EC = 12

CH = 5

HE = 7

Step-by-step explanation:

The complete question is

The diameters of circles A, C and E are 32 cm, 24 cm and 14 cm respectively.

Which of the following statements are true? Select all that apply.

•AG = 4

•GC = 10

•AH = 21

•EC = 12

•EH = 5

•CH = 5

•HE = 7

The picture of the question in the attached figure

Verify each statement

1) AG = 4

we know that

$AG=AC-GC$

$AC=32\2=16\ cm$ ----> radius of circle A

$GC=24/2=12\ cm$ ----> radius of circle C

substitute

$AG=16-12=4\ cm$

therefore

The statement is true

2) GC = 10

we know that

$GC=24/2=12\ cm$ ----> radius of circle C

therefore

The statement is false

3) AH = 21

we know that

$AH=AC+CH$

we have

$AC=16\ cm$ ----> radius of circle A

$CH=CE-HE$

$CE=12\ cm$ ----> radius of circle C

$HE=14/2=7\ cm$ ----> radius of circle E

so

$CH=12-7=5\ cm$

$AH=16+5=21\ cm$

therefore

The statement is true

4) EC = 12

we know that

$EC=24/2=12\ cm$ ----> radius of circle C

therefore

The statement is true

5) EH = 5

we know that

$EH=14/2=7\ cm$ ----> radius of circle E

therefore

The statement is false

6) CH = 5

we know that

$CH=CE-HE$

$CE=12\ cm$ ----> radius of circle C

$HE=14/2=7\ cm$ ----> radius of circle E

so

$CH=12-7=5\ cm$

therefore

The statement is true

7) HE = 7

we know that

$HE=14/2=7\ cm$ ----> radius of circle E

therefore

The statement is true

3 0

3 years ago

Please help me on this quick!! Thanks and please show work.

FinnZ [79.3K]

The two parallel bases b1 and b2 are
b1 = 12
b2 = 9
the order of which base you pick doesn't matter

The height is h = 10 and it's perpendicular to each base.

The area is...

A = (1/2)*h*(b1+b2)
A = (1/2)*10*(12+9)
A = (1/2)*10*(21)
A = 5*21
A = 105

Final Answer: B) 105 square centimeters

8 0

3 years ago

Diego measured the length of a pen to be 21 cm. The actual length of the pen is 23 cm. Which of these is closest to the percent

Colt1911 [192]

B hope it helps you

4 0

3 years ago