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dlinn [17]
3 years ago
10

TRUE OR FALSE: if 6 is a factor of a number,then 3 is a factor of the number.

Mathematics
2 answers:
hodyreva [135]3 years ago
8 0
True I believe......
NemiM [27]3 years ago
6 0
Yes it is............
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Use polar coordinates to find the limit. [if (r, θ) are polar coordinates of the point (x, y) with r ≥ 0, note that r → 0 as (x,
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3 years ago
Using approciate properties find -4/7*3/5+4/7*-1/5+2/5*-4/5
slega [8]

Answer: 0.548

Step-by-step explanation:

First you need to remember the formula for PEMDAS(Parenthesis,exponents,multiplication,divison,addition,subtractio)

you can do either multiplication or divison whichever comes first, same with addition+subtraction.

the underlined means to simplify

1.<u>-0.57x3</u>/5+4/7x-1/5+2/5x-4/5

2.<u>-1.71/5</u>+4/7x-1/5+2/5x-4/5

3.-0.342+<u>4/7</u>x-1/5+2/5x-4/5

4.-0.342+0.57x<u>-1/5</u>+2/5x-4/5

5.-0.342+<u>0.57x-0.2</u>+2/5x-4/5

6.-0.342+0.114+<u>2/5</u>x-4/5

7.-0.342+0.114+<u>0.4x-4</u>/5

8.-0.342+0.114+<u>-1.6/5</u>

9.<u>-0.342+0.114</u>+-0.32

10.<u>-0.228+-0.32=-0.548</u>

<u>i did this all in one go so......</u>

8 0
3 years ago
20 points Return to questionItem 4Item 4 20 points Police records in the town of Saratoga show that 13 percent of the drivers st
Sladkaya [172]

Answer:

a) 0.1423

b) 0.2977

c) 0.56

Step-by-step explanation:

For each driver stopped for speeding, there are only two possible outcomes. Either they have invalid licenses, or they do not. The probability of a driver having an invalid license is independent from other drivers. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

13 percent of the drivers stopped for speeding have invalid licenses.

This means that p = 0.13

14 drivers are stopped

This means that n = 14

(a) None will have an invalid license.

This is P(X = 0)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{14,0}.(0.13)^{0}.(0.87)^{14} = 0.1423

(b) Exactly one will have an invalid license.

This is P(X = 1)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{14,1}.(0.13)^{1}.(0.87)^{13} = 0.2977

(c) At least 2 will have invalid licenses.

Either less than 2 have invalid licenses, or at least 2 does. The sum of the probabilities of these events is decimal 1. Mathematically, this is

P(X < 2) + P(X \geq 2) = 1

We want P(X \geq 2)

So

P(X \geq 2) = 1 - P(X < 2)

In which

P(X < 2) = P(X = 0) + P(X = 1) = 0.1423 + 0.2977 = 0.44

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.44 = 0.56

8 0
3 years ago
There are 20 diamonds and 15 squares what is the ratio of squares to diamonds (REDUCE)
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Its 15 to 20 which goes to 3 to 4
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A because your not dividing it by 5 your subtracting 5 from k divided by 2
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