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dlinn [17]
3 years ago
10

TRUE OR FALSE: if 6 is a factor of a number,then 3 is a factor of the number.

Mathematics
2 answers:
hodyreva [135]3 years ago
8 0
True I believe......
NemiM [27]3 years ago
6 0
Yes it is............
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scarlet is trying to find the height of a dam. she stands 90 meters away from the dam and records the angle of elevation to the
Harlamova29_29 [7]
Make a drawing with a right triangle.

The opposite side, y, is the height of the dam less 1.65 m

The base or adjacent side is 90 m

The angle between the two sides is 90 m.

Then tan (26) = y / 90

y = 90 tan(26) = 90 (0.4877) = 43.90 m

The height of the dam is 43.90m + 1.65m = 45.55 m
5 0
3 years ago
Find the area of each parallelogram<br><br> Please help with these thank you
hammer [34]
A=8
B=10

Hope this helps :D
4 0
3 years ago
A bedroom door in the house has the same dimension as the front door but the length is 30 inches rather than 36 inches how much
arsen [322]

Answer:

6/5

Step-by-step explanation:

Calculate the volume by multiplying the measured length and width of the space together, then multiply the result by the height of the room. From the example, 10 * 25 feet = 250 square feet, and 5 * 10 feet = 50 square feet.

5 0
2 years ago
I need help finding this answer because I am pretty sure it’s C but I don’t know
malfutka [58]

Answer: A) -9

Step-by-step explanation:

If x = -2

Then 3^{x} = 3^{-2}

So, it is -9

5 0
3 years ago
Please someone help me with this word problem for my math class T.T
olga55 [171]

Answer:

<u>Perimeter</u>:

= 58 m (approximate)

= 58.2066 or 58.21 m (exact)

<u>Area:</u>

= 208 m² (approximate)

= 210.0006 or 210 m² (exact)

Step-by-step explanation:

Given the following dimensions of a rectangle:

length (L) = \sqrt{252} meters

width (W) = \sqrt{175} meters

The formula for solving the perimeter of a rectangle is:

P  = 2(L + W) or 2L + 2W

The formula for solving the area of a rectangle is:

A = L × W

<h2>Approximate Forms:</h2>

In order to determine the approximate perimeter, we must determine the perfect square that is close to the given dimensions.  

13² = 169

14² = 196

15² = 225

16² = 256

Among the perfect squares provided, 16² = 256 is close to 252 (inside the given radical for the length), and 13² = 169 (inside the given radical for the width).  We can use these values to approximate the perimeter and the area of the rectangle.

P  = 2(L + W)

P = 2(13 + 16)

P = 58 m (approximate)

A = L × W

A = 13 × 16

A = 208 m² (approximate)

<h2>Exact Forms:</h2>

L = \sqrt{252} meters = 15.8745 meters

W = \sqrt{175} meters = 13.2288 meters

P  = 2(L + W)

P = 2(15.8745 + 13.2288)

P = 2(29.1033)

P = 58.2066 or 58.21 m

A = L × W

A = 15.8745 × 13.2288

A = 210.0006 or 210 m²

8 0
3 years ago
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