2(x)^2 - 2(x) - 12 = ?
2(x)^2 - 2(x) - 12
(x)^2 - 6 - x
Multiply ↪1 (-6) = -6
1 + -6 = -5 , right?
-3 + 2 = -1, right?
After we have pulled out the like terms we have to add/subtract! x(x) - 3
Search for the common denominator
2(x) - 3
You can add up 4 for your terms
x + 2 (x - 3)
Make sure you solve this↪ 2 = 0
x + 2 = ?
x + 2 = 0
We have found the first; x = -2
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Since, this one has a single variable, I'll make the step easier and quicker
Solve this part ↪ x-3 = 0
If we had the number 3 to your sides we would have found the outcome of the next x
So, the second x is 3
So, therefore your answer would have to be x =-2 ; x = 3 (most likely option C.)
Easy tip: just multiply seven and four together!
7•4=28
So both seven and four fit into 28
<span>P(9,12): For all intents and purposes, the hypotenuse is "r", the opposite side is "y", and the adjacent side is "x".
x = 9 (from the P(9,12))
y = 12 (also from the point)
Using the Pythagorean Theorem, you find out that r = 15.
Therefore, since cos θ = x/r
cos θ = 9/15 or 3/5
Answer: 3/5</span>
