to get the LCD we should start by doing a quick prime factoring of each denominator, as you see in the picture below.
the factors in red are the common factors to all values, and they are used in the LCD only once, the other not common factors in blue, they're used in the LCD.
Median of 15
(14 + b) / 2 = 15
14 + b = 15 * 2
14 + b = 30
b = 30 - 14
b = 16
range of 30
c - a = 30....c = 30 + a
mean of 18
(a + 8 + 14 + 16 + 26 + c) / 6 = 18
(a + 8 + 14 + 16 + 26 + (30 + a)) / 6 = 18
(2a + 94) / 6 = 18
2a + 94 = 18 * 6
2a + 94 = 108
2a = 108 - 94
2a = 14
a = 14/2
a = 7
c - a = 30
c - 7 = 30
c = 30 + 7
c = 37
check..
7,8,14,16,26,37
median = (16 + 14) / 2 = 30/2 = 15 ...correct
range = 37 - 7 = 30...correct
mean(average) = (7 + 8 + 14 + 16 + 26 + 37) / 6 = 108/6 = 18...correct
so a = 7, b = 16, and c = 37
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I must assume that you meant the following:
10(Q-3R)
P = ----------------
R
Multiplying both sides by R, we get PR = 10R(Q-3R), or PR = 10RQ - 30R^2.
Rearranging these terms so that powers of R are in descending order:
30R^2 - 10RQ + PR = 0
Factoring out R, we get
R(30R - 10Q + P) = 0. This has two solutions:
R = 0, and 10Q - P
30R = 10Q - P, so that R = --------------
30
Answer:

Step-by-step explanation:
Given
Geometric Sequence (GP)


Required
Determine T₁₂
The nth term of a GP is calculated as thus;

In this case;
;
and 
Substitute these values in the above formula



Open the bracket


<em>Hence, the 12th term of the sequence is </em>