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Vilka [71]
4 years ago
5

What are the solutions to the equation 2x^2 - 2x - 12 = 0?

Mathematics
1 answer:
pantera1 [17]4 years ago
5 0
2(x)^2 - 2(x) - 12 = ?
  
2(x)^2 - 2(x) - 12

(x)^2 - 6 - x

Multiply ↪1 (-6) = -6

1 + -6 = -5 , right?

-3 + 2 = -1, right?

After we have pulled out the like terms we have to add/subtract!   x(x) - 3

Search for the common denominator
2(x) - 3

You can add up 4 for your terms
x + 2 (x - 3)

Make sure you solve this↪ 2 = 0

x + 2 = ?
x + 2 = 0
We have found the first; x = -2
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Since, this one has a single variable, I'll make the step easier and quicker

Solve this part ↪    x-3 = 0 
If we had the number 3 to your sides we would have found the outcome of the next x
                    
So, the second x is 3 

So, therefore your answer would have to be x =-2 ; x = 3 (most likely option C.)



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What is the LCD of 1/9,1/27,8/45<br> HELP ASAP PLEASE
Alla [95]

to get the LCD we should start by doing a quick prime factoring of each denominator, as you see in the picture below.

the factors in red are the common factors to all values, and they are used in the LCD only once, the other not common factors in blue, they're used in the LCD.

4 0
3 years ago
I need help finding the whole question, i'm not sure if what i've done already if correct, thanks
artcher [175]
Median of 15

(14 + b) / 2 = 15
14 + b = 15 * 2
14 + b = 30
b = 30 - 14
b = 16

range of 30
 c - a = 30....c = 30 + a

mean of 18
(a + 8 + 14 + 16 + 26 + c) / 6 = 18
(a + 8 + 14 + 16 + 26 + (30 + a)) / 6 = 18
(2a + 94) / 6 = 18
2a + 94 = 18 * 6
2a + 94 = 108
2a = 108 - 94
2a = 14
a = 14/2
a = 7

c - a = 30
c - 7 = 30
c = 30 + 7
c = 37

check..
7,8,14,16,26,37
median = (16 + 14) / 2 = 30/2 = 15 ...correct
range = 37 - 7 = 30...correct
mean(average) = (7 + 8 + 14 + 16 + 26 + 37) / 6 = 108/6 = 18...correct

so a = 7, b = 16, and c = 37

3 0
3 years ago
NEED HELP PLEASE AHHH! A system of equations and it’s solution are given below
vfiekz [6]
Just download the photomath app it will solve it for u !
6 0
3 years ago
Make R the subject<br> <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7BP%3D10%28Q-3R%29%7D%7BR%7D" id="TexFormula1" title=" \frac
Naddik [55]

I must assume that you meant the following:

10(Q-3R)

P = ----------------

R

Multiplying both sides by R, we get PR = 10R(Q-3R), or PR = 10RQ - 30R^2.

Rearranging these terms so that powers of R are in descending order:

30R^2 - 10RQ + PR = 0

Factoring out R, we get

R(30R - 10Q + P) = 0. This has two solutions:

R = 0, and 10Q - P

30R = 10Q - P, so that R = --------------

30

8 0
3 years ago
Find t12 for a geometric sequence where t1=2+2i and r=3
vfiekz [6]

Answer:

T_{12} = 354294 + 354294i

Step-by-step explanation:

Given

Geometric Sequence (GP)

T_1 = 2 + 2i

r = 3

Required

Determine T₁₂

The nth term of a GP is calculated as thus;

T_n = ar^{n-1}

In this case;

n = 12;  r = 3 and a = T_1 = 2 + 2i

Substitute these values in the above formula

T_{12} = (2 + 2i) * 3^{12-1}

T_{12} = (2 + 2i) * 3^{11}

T_{12} = (2 + 2i) * 177147

Open the bracket

T_{12} = 177147 * 2 + 177147 * 2i

T_{12} = 354294 + 354294i

<em>Hence, the 12th term of the sequence is </em>T_{12} = 354294 + 354294i

8 0
3 years ago
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