Answer: 5329, 3025, 2304
Step-by-step explanation:
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The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
<h3>What is the radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.?</h3>
Generally, the equation for side lengths AB is mathematically given as
Triangle ABC has side lengths
Where
- AB = 65,
- BC = 33,
- AC = 56.
Hence
r √ 2 · (89 √ 2/2 − r √ 2) = r(89 − 2r),
r = 89 − 65
r= 24.
In conclusion, The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
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3.60 / 60cm = .06/cm or 6 cents per centimeter
100cm = 1m
$.06 * 100cm = $6.00 / m
100m = 100 * $6.00
= $600
The weight would be converted to 30 pounds on the moon
Show the triangle in the picture
