All categories

3 years ago

What is the volume of the water contained in the cylinder?

Mathematics

1 answer:

Margarita [4]3 years ago

3 0

Answer:

Vf = 118.365 m3

Step-by-step explanation:

Vcil = Pi*[(20)^2]*(100=

Vcil = 125.600 m3

Vesf = (4/3)*Pi*(12)^3

Vesf = 7235 m3

Then

Vf = Vci - Vesf

Vf = 125.600 - 7235

Vf = 118365 m3

Best regards

You might be interested in

Evaluate 4 - 6 + 9 - 3

omeli [17]

$4 - 6 + 9 - 3$

$= 4$

3 0

3 years ago

Which is the solution to the inequality?

n200080 [17]

y < –12

Solution:

Step 1: Given inequality is y + 15 < 3.

To find the solution to the inequality.

Step 2: Subtract –15 on both sides to equal the expression.

⇒ y + 15 –15 < 3 –15

Step 2: Using addition identity property, any number adding with zero gives the number itself.

⇒ y + 0 < –12

⇒ y < –12

Hence the solution to the inequality is y < –12.

4 0

3 years ago

Read 2 more answers

Ashley makes 6 gallons of broth for the restaurant, she serves 30 cups of broth to guests. how many cups of soup are left over?

CaHeK987 [17]

Answer:

66 cups

Step-by-step explanation:

16 cups in 1 gallon

16*6 = 96 cups in 6 gallons

96 - 30 = 66

7 0

2 years ago

Plz help me with this

Setler79 [48]

Answer: x = 8

(the correct answer was not provided as an option)

<u>Step-by-step explanation:</u>

$log_2(x-6)+log_2(x-4)=log_2(x)\\\\log_2[(x-6)(x-4)]=log_2(x)\\\\(x-6)(x-4)=x\\\\x^2-10x+24=x\\\\x^2-11x+24=0\\\\(x-3)(x-8)=0\\\\x=3\qquad x=8\\\\\\\text{The term after the log symbol (inside the parenthesis) must be greater than 0!}\\\\Check:\\3-6>0\ \text{FALSE --- so 3 is not a valid solution}\\\\8-6>0\ \text{TRUE}\\8-4>0\ \text{TRUE}\\8>0\ \text{TRUE --- 8 is a valid solution because it is true for all}$

8 0

2 years ago

Find the distance between the two points. Round to the nearest tenth if necessary. (6, 11), (0, 3) a. 10 b. 14 c. 15 d. 100

lorasvet [3.4K]

Answer: option a

Step-by-step explanation:

You must apply the formula for calculate the distance between the two points. which is shown below:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Therefore, keeping on mind that the points given in the problem are (6, 11), (0, 3), when you substitute values into the formula shown above, you obtain that the distance between these two points is the following:

$d=\sqrt{(0-6)^2+(3-11)^2}\\d=10$

8 0

2 years ago

Read 2 more answers