(10 * 50) / 100
Multiply 10 and 50
500/100
500 divide by 100
The answer is 5
I would argue that it does due to that if it increased, it's either from a 30% chance that nothing changed or that the teachers did it. Since 100-30=70, there's a 70 percent chance that the teaching effect did work!
Answer:
Margin of error of 0.0485 hours.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
That is z with a pvalue of 
, so Z = 1.96.
Now, find the margin of error M as such
In which 
is the standard deviation of the population and n is the size of the sample.
In this question:
The margin of error is of:
Margin of error of 0.0485 hours.
r = -3/4p - 18/5
(or you could put 3.6 or 3 3/5 instead of 18/5)
2 - 3/4p = 5/6r + 5
-5 -5
-3 - 3/4p = 5/6r
/(5/6) /(5/6)
-18/5 - 3/4p = r
-3/4p - 18/5 = r
Answer:
X=-12
Step-by-step explanation:
9-16-5=X
-12=X
X=-12
