x + 3 < 4x - 12 or 4x - 12 < 20
<u>-x </u> <u> -x </u> <u> +12 </u> <u>+12 </u>
3 < 3x - 12 or 4x < 32
<u> +12</u> <u> +12 </u> <u> ÷4 </u> <u>÷4 </u>
15 < 3x or x < 8
<u> ÷3</u> <u>÷3 </u>
5 < x
5 < x < 8
Graph: 5 o---------------o 8
Two fractions equivalent to 2/6 are...
1/3 and 4/12
Hope this helps!! :)
Answer: 4/5 of a box of candy
Step-by-step explanation:
Justine sold 1¹/₅ times the ²/₃ of a box of candy that Grayson sold.
Justin sold;
= 1¹/₅ * ²/₃
= 6/5 * 2/3
= 12/15
= 4/5 of a box of candy
The inverse function is equal to f-1(x) = (x - 1)/3 and the value at f-1(6) is equal to 5/3.
To find the inverse, you need to switch the f(x) and x in the equation. Then you can solve for the new f(x). The result will be the inverse (f-1)
f(x) = 3x + 1 ----> Switch f(x) and x
x = 3f(x) + 1 ----> Subtract 1
x - 1 = 3f(x) ----> Divide by 3.
f-1(x) = (x - 1)/3
Now that we have the inverse, we can plug 6 in to get the value at f-1(6).
f-1(x) = (x - 1)/3
f-1(6) = (6 - 1)/3
f-1(6) = 5/3
First, you multiply 600 and .20 to find 20% of 600 rupees, which is 120 rupees. Second, you subtract the 20%, (120 rupees) from 600 rupees, which is 480 rupees. After that, you have the original selling price of 480 rupees that the man purchased the article for, but the question is stating that he gained 15% of the original sales price. So, you multiply 480 and .15 to find 15% of 480 rupees, which is 72. However, he GAINED more money than what he payed for the article so you add 72 rupees to 480 rupees to get 552 rupees. In conclusion, the man sells the article for 552 rupees.