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dangina [55]
3 years ago
11

If a doughnut contains 1.8 moles of sugar (C6H12O6), how many sugar molecules are in a box of one dozen doughnuts?

Chemistry
1 answer:
barxatty [35]3 years ago
5 0

Answer:

130.1 x 10²³ molecules of sugar  

Explanation:

One dozen = 12 donuts

1 doughnut = 1.8 moles of sugar

12 doughnut = (1.8 x 12) moles of sugar = 21.6 moles of sugar

1 mole of any substance contains Avogadro’s number (6.023 x 10²³) of molecules.

1 mole of sugar = 6.023 x 10²³ molecules of sugar

21.6 moles of sugar = (6.023 x 10²³ x 21.6) molecules of sugar  

                                 = 130.1 x 10²³ molecules of sugar  

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$200 - $12.80 = $187.20

5 0
4 years ago
How many liters of oxygen gas, at standard
Karo-lina-s [1.5K]

Answer:

Explanation:

  • For the balanced reaction:

<em>4Fe(s) + 3O₂(g) → 2Fe₂O₃(s)​.</em>

It is clear that 4 mol of Fe react with 3 mol of O₂ to produce 2 mol of Fe₂O₃.

  • Firstly, we need to calculate the no. of moles of 35.8 grams of Fe metal:

no. of moles of Fe = mass/molar mass = (35.8 g)/(55.845 g/mol) = 0.64 mol.

  • Now, we can find the no. of moles of O₂ is needed to react with the proposed amount of Fe:

<em><u>Using cross multiplication:</u></em>

4 mol of Fe is needed to react with → 3 mol of O₂, from stichiometry.

0.64 mol of Fe is needed to react with → ??? mol of O₂.

∴ The no. of moles of O₂ needed = (3 mol)(0.64 mol)/(4 mol) = 0.48 mol.

  • Finally, we can get the volume of oxygen using the information:

<em>It is known that 1 mole of any gas occupies 22.4 L at standard P and T (STP).</em>

<em></em>

<em><u>Using cross multiplication:</u></em>

1 mol of O₂ occupies → 22.4 L, at STP conditions.

0.48 mol of O₂ occupies → ??? L.

∴ The no. of liters of O₂ = (0.48 mol)(22.4 L)/(1 mol) = 10.752 L.

5 0
3 years ago
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sleet_krkn [62]

Answer:

n = 0.0814 mol

Explanation:

Given mass, m = 35.7g

The molar mass of Tin(IV) bromate, M = 438.33 g/mol

We need to find the number of moles of bromine. We know that,

No. of moles = given mass/molar mass

So,

n=\dfrac{35.7}{438.33}\\\\n=0.0814\ mol

So, there are 0.0814 moles of bromine in 35.7g of  Tin(IV) bromate.

3 0
3 years ago
one of the tallest dog breeds is the great dane which stands over a meter tall. one of the shortest is the pomeranian which stan
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3 years ago
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allsm [11]

Answer:

4. they have the same number of protons

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