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3 years ago

If a doughnut contains 1.8 moles of sugar (C6H12O6), how many sugar molecules are in a box of one dozen doughnuts?

Chemistry

1 answer:

barxatty [35]3 years ago

5 0

Answer:

130.1 x 10²³ molecules of sugar

Explanation:

One dozen = 12 donuts

1 doughnut = 1.8 moles of sugar

12 doughnut = (1.8 x 12) moles of sugar = 21.6 moles of sugar

1 mole of any substance contains Avogadro’s number (6.023 x 10²³) of molecules.

1 mole of sugar = 6.023 x 10²³ molecules of sugar

21.6 moles of sugar = (6.023 x 10²³ x 21.6) molecules of sugar

= 130.1 x 10²³ molecules of sugar

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9.27 mol of oxygen is equal to______molecules of oxygen <br> Please help I need it

bixtya [17]

<h3>Answer:</h3>

5.58 × 10²⁴ molecules O₂

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

9.27 mol O₂ (Oxygen)

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

Set up: $\displaystyle 9.27 \ mol \ O_2(\frac{6.022 \cdot 10^{23} \ molecules \ O_2}{1 \ mol \ O_2})$
Multiply/Divide: $\displaystyle 5.58239 \cdot 10^{24} \ molecules \ O_2$

<u>Step 4: Check</u>

<em>Follow sig fig rules. We are given 3 sig figs.</em>

5.58239 × 10²⁴ molecules O₂ ≈ 5.58 × 10²⁴ molecules O₂

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3 years ago

Why is the speed of these particles deffirent in each state

monitta

Answer:

due to difference ic kinetic energy

Explanation:

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3 years ago

How could we stop an asteroid that we know was going to hit Earth?<br><br><br> Pls help ASAP

myrzilka [38]

Answer:

An object with a high mass close to the Earth could be sent out into a collision course with the asteroid, knocking it off course. When the asteroid is still far from the Earth, a means of deflecting the asteroid is to directly alter its momentum by colliding a spacecraft with the asteroid.

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3 years ago

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In a certain experiment, 28.0 mL of 0.250 M HNO3and 53.0 mL of 0.320 M KOH are mixed. Calculate the number of moles of water for

Xelga [282]

Answer:

The number of moles of water formed in the resulting reaction is 6.03

[H+]: 37,2 M

[OH-]: 37,2 M

Explanation:

HNO3 + KOH ----> KNO3 + H2O

First, we must discover the limiting reagent and we need to find out the moles, we use for this.

Moles that are used = Molarity / volume

HNO3 : 0,250 mol/L / 0,028L = 8,93 moles

KOH : 0,320 mol/L / 0,053L = 6,03 moles

The ratio of the reagents by stoichiometry is 1 to 1, so the limiting reagent is KOH, if I need 1 mole of nitric per mole of KOH, for every 8.93 moles I will need the same. However I have only 6.03 moles of KOH

The ratio of the reagents/products by stoichiometry is 1 to 1 so if I need 1 mol of KOH to make 1 mol of Water, 6,03 moles of KOH are used to make 6,03 moles of H2O.

The equilibrium of water is this:

2H2O ⇄ H3O+ + OH-

2 moles of water are broken down into 1 mole of hydronium (H3O +) and 1 mole of hydroxyl (OH-)

6,03 moles of water are broken down into the half of those moles, so we have 3,015 moles of H3O+ and 3,015 moles of OH- but these moles are in 81,0 mL (the volume of the two solutions, 28 mL + 53 mL)

We must find out the moles in 1000 mL (1 L) so let's apply the rule of three.

81 mL ____ 3,015 moles

1000 mL ___ ( 1000 . 3,015) /81 = 37,2 M

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3 years ago

What is the electron configuration of the element with 27 protons?

adelina 88 [10]

<span>The electronic configuration of cobalt is :1s2 2s2 2p6 3s2 3p6 3d7 4s2 </span>

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3 years ago

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