CIO4 statements best describe the Lewis structure.
<h3>What is Lewis Structure?</h3>
A Lewis Structure is a very simplified presentation of the valence shell electrons in a molecule. It is used to show how the electrons are organized around particular atoms in a molecule. Electrons are displayed as "dots" or for bonding electrons as a line between the two atoms.
- Lewis structure does NOT endeavor to explain the geometry of molecules, how the bonds compose, or how the electrons are transmitted between the atoms.
- It is the easiest and most limited theory on electronic format.Lewis systems show separately atom and its position in the structure of the molecule using its chemical symbol. Lines are drawn between atoms that are connected (pairs of dots can be used instead of sequences). Excess electrons that form lone pairs are defined as pairs of dots and are positioned next to the atoms.
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Answer:
Option A. FeCl3
Explanation:
The following data were obtained from the question:
Mass of iron (Fe) = 6.25g
Mass of the compound formed = 18g
From the question, we were told that the compound formed contains chlorine. Therefore the mass of chlorine is obtained as follow
Mass of chlorine (Cl) = Mass of compound formed – Mass of iron.
Mass of chlorine (Cl) = 18 – 6.25
Mass of chlorine (Cl) = 11.75g
The compound therefore contains:
Iron (Fe) = 6.25g
Chlorine (Cl) = 11.75g
The empirical formula for the compound can be obtained by doing the following:
Step 1:
Divide by their molar mass
Fe = 6.25/56 = 0.112
Cl = 11.75/35.5 = 0.331
Step 2:
Divide by the smallest
Fe = 0.112/0.112 = 1
Cl = 0.331/0.112 = 3
The empirical formula for the compound is FeCl3
<span>More surface area --> more molecules of the solute in contact with the solvent --> more chance for a solvent molecule to collide with the solute molecules --> dissolves faster
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Answer:
0.24 M
Explanation:
Molarity = Moles solute / Liters solution
Step 1: Identify variables
400 mL = Liters solution
0.60 moles = Moles solute
Step 2: Identify conversions
1 L = 1000 mL
Step 3: Convert mL to L
400mL(1 L/1000mL) = 0.4 L
Step 4: Find molarity
M = (0.4 L)(0.60 mol) = 0.24 M
