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slavikrds [6]
3 years ago
7

Question 1 1 pts How many mols of bromine are present in 35.7g of Tin(IV) bromate?

Chemistry
1 answer:
sleet_krkn [62]3 years ago
3 0

Answer:

n = 0.0814 mol

Explanation:

Given mass, m = 35.7g

The molar mass of Tin(IV) bromate, M = 438.33 g/mol

We need to find the number of moles of bromine. We know that,

No. of moles = given mass/molar mass

So,

n=\dfrac{35.7}{438.33}\\\\n=0.0814\ mol

So, there are 0.0814 moles of bromine in 35.7g of  Tin(IV) bromate.

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