Answer:
The steps to do :
9x^2-6x+8=0 what is the fifth step in solving this equation
1 answer:
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In order to determine if the events are independent or not we need to find the conditional probabilities.
The conditional probability of event A, given event B is denoted as P(A|B)
P(A*B) indicates P(A and B)
Using the values, we get:
Since P(A|B) is not equal to P(A) this indicates that occurrence of event B has an impact on the occurrence of event A. This shows that the two events are dependent.
Therefore, the correct option is the second one.
2. A and B are not independent events because P(A∣∣B)≠P(A)
The conditional probability of event A, given event B is denoted as P(A|B)
P(A*B) indicates P(A and B)
Using the values, we get:
Since P(A|B) is not equal to P(A) this indicates that occurrence of event B has an impact on the occurrence of event A. This shows that the two events are dependent.
Therefore, the correct option is the second one.
2. A and B are not independent events because P(A∣∣B)≠P(A)
Answer:
a) 0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.
b) 0.996 is the probability that more than half of the vehicles carry just one person.
Step-by-step explanation:
We are given the following information:
A) Binomial distribution
We treat vehicle on road with one passenger as a success.
P(success) = 64% = 0.64
Then the number of vehicles follows a binomial distribution, where
where n is the total number of observations, x is the number of success, p is the probability of success.
Now, we are given n = 10
We have to evaluate:
0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.
B) By normal approximation
Sample size, n = 92
p = 0.64
We have to evaluate the probability that more than 47 cars carry just one person.
After continuity correction, we will evaluate
Calculation the value from standard normal z table, we have,
0.996 is the probability that more than half out of 92 vehicles carry just one person.