Question

Find the volume for the regular pyramid. V =

Answer 1

Answer:

$16\sqrt{2}\\3$

Answer 2

Answer:

$Volume=\frac{16\sqrt{2} }{3}units^{3}$

Step-by-step explanation:

∵ The volume of the pyramid = 1/3 base area  × height

∵ The base is equilateral Δ with side length 4

∴ The area of the bast = 1/4 × 4² × √3 = 4√3 units²

To get the height of the pyramid draw it from the vertex of the top of the pyramid ⊥ to the base on the centro-id of the base which divides the height of the triangle two ratio 2:1 from the vertex of the triangle

∵ The height of the base = √(4² - 2²) =√12 = 2√3

∴ 2/3 the height = 4√3/3 ⇒ (2:1 means 2/3 from the height)

∴ The height of the pyramid = √[4² - (4√3/3)²] = √[16 - 48/9]

∴ h = 4√2/√3 (4√6/3 in its simplest form)

∴ V = 1/3 × 4√3 × 4√2/√3 = 16√2/3 units³

∴ $V = \frac{16\sqrt{2} }{3}$