A theater company with 9 actors is putting on a play that has 3 roles. In how many different ways can the director assign actors

Question

iren2701 [21]

3 years ago

10

A theater company with 9 actors is putting on a play that has 3 roles. In how many different ways can the director assign actors

to those roles?

Mathematics

2 answers:

steposvetlana [31] · Answer 1 · 2022-08-16T17:52:38+03:00

steposvetlana [31]3 years ago

6 0

9!/(3!*6!)=7*8*9/6=84

Cerrena [4.2K] · Answer 2 · 2022-08-16T16:41:39+03:00

He has 9 choices for the first role, and that leaves him 8 people to choose for the second so he has 9*8 = 72 choices for the first two roles; that leaves 7 possible choices for the third role so that gives him 9*8*7 choices or 504 different ways he can assign the roles. i think this is correct.