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iren2701 [21]
2 years ago
10

A theater company with 9 actors is putting on a play that has 3 roles. In how many different ways can the director assign actors

to those roles?
Mathematics
2 answers:
steposvetlana [31]2 years ago
6 0
9!/(3!*6!)=7*8*9/6=84
Cerrena [4.2K]2 years ago
5 0
He has 9 choices for the first role, and that leaves him 8 people to choose for the second so he has 9*8 = 72 choices for the first two roles; that leaves 7 possible choices for the third role so that gives him 9*8*7 choices or 504 different ways he can assign the roles. i think this is correct. 







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2) Binary    25= (11001)_2

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4) Hexadecimal   25= (19)_{16}

Step-by-step explanation:

Given : Integer is 25                      

To find : Represent integer in decimal, binary, octal, and hexadecimal formats.

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2) Integer into binary - To convert into binary the base goes to 2, it form in 0 and 1 and we divide integer by 2.

Divide 25 by 2 and note down the remainders.

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2 | 12    R=1    ←

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2 | 3      R=0  ↑

2 | 1  →   R=1   ↑

So,   25= (11001)_2

3) Integer into octal - To convert into octal the base goes to 8 and we divide integer by 8.

Divide 25 by 8 and note down the remainders.

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Divide 25 by 16 and note down the remainders.

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