I need Help please!!!!

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th

iren [92.7K]

9514 1404 393

Answer:

32 feet

Step-by-step explanation:

0 seconds after launch, the rocket is still sitting on the tower. Its height is...

y = -16(0^2) +57(0) +32

y = 0 + 0 + 32 = 32

The rocket was launched from a tower 32 feet high.

6 0

3 years ago

Help me with this:((((

Hoochie [10]

Activity 3
1) 2m^2(4m^2 + 3m + 2)
2) (x + 4)^2 (x - 4)
3) (x + 9)(x - 7)
4) 5y(17y - 4z)
5) (2x - y)(6x + 5y)

Activity 4
1) 80 units because when you sub h = 9, you get 400 as the answer and because it’s a square, you square root 400 which is 20 units per side.
2) x = 7cm because when you multiply (x + 5)(x - 3), you get x^2 + 2x - 15 = 48 and when you solve it you get x is equal to 7, -9, because the length of the rectangle is positive x is equal to 7.
3) the binomial would be (9x + 1)^2.

4 0

3 years ago

To find the standard deviation of the diameter of wooden dowels, the manufacturer measures 19 randomly selected dowels and find

loris [4]

Answer:

Option D - $[0.12$

Step-by-step explanation:

Given : The manufacturer measures 19 randomly selected dowels and finds the standard deviation of the sample to be s=0.16.

To find : The 95% confidence interval for the population standard deviation sigma?

Solution :

Number of sample n=19

The degree of freedom is Df=n-1=19-1=18

The standard deviation of the sample is s=0.16

Applying chi-square table to find critical value,

Upper critical value of $\chi^2$ is $UC=\chi(\frac{0.05}{2},18) = 31.5264$

Lower critical value of $\chi^2$ is

$LC=\chi(1-\frac{0.05}{2},18) = 8.2307$

Lower limit of the 95% confidence interval for the population variance

$L=\frac{(df)\times (s^2)}{UC}$

$L=\frac{18\times (0.16^2)}{31.5264}$

$L=\frac{18\times0.0256}{31.5264}$

$L=\frac{0.4608}{31.5264}$

$L=0.0146$

Upper limit of the 95% confidence interval for the population variance

$U=\frac{(df)\times(s^2)}{LC}$

$U=\frac{18\times (0.16^2)}{8.2307}$

$U=\frac{18\times0.0256}{8.2307}$

$U=\frac{0.4608}{8.2307}$

$U=0.0559$

So, The 95% confidence interval for the population variance is [0.0146, 0.0560]

Now, The 95% confidence interval for the population standard deviation is

$[\sqrt{0.0146}$

$[0.1208$

or $[0.12$

Therefore, Option D is correct.

The 95% confidence interval for the population standard deviation is $[0.12$

6 0

3 years ago

Please Help!!!<br><br> What two numbers go there?

marshall27 [118]

The answer is 9/7!! Hope it helps

6 0

3 years ago

Dont need any of the explaining just want an answer

Alex787 [66]

The change in average height of the trees on the farm with respect to the number of years since the trees were planted is = 7ft/yr.

<h3>What is the linear relationship?</h3>

A statistical word used to express a straight-line relationship between two variables is a linear relationship (or linear association).
Graphs and mathematical equations of the form y = mx + b can both be used to represent linear relationships.
In everyday life, linear relationships are quite prevalent.

The midpoint of the axis is=

10+24/2
34/2
17

In the intercept form-

y= mx+b
y= mx+3
y= mx +3
10 =m(1) + 3

subtracting 3 from both sides-

7=m
Y = 7x+3

Hence, the rate of change is 7ft/yrs.

Know more about linear relationship click here:

brainly.com/question/13828699

#SPJ9

8 0

1 year ago