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igomit [66]
3 years ago
11

Write a decimal that is equivalent to three and ten hundredths

Mathematics
1 answer:
IRINA_888 [86]3 years ago
6 0
The answer is 3.3. and represents a decimal and tenths is the place value right after the decimal
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A square dance floor has a perimeter of 120 yards. What is the length of a diagonal of the dance floor?
Crazy boy [7]

Answer:

Hey!

Your answer is C.42.4yd

Step-by-step explanation:

There are 2 ways you can work this on out...

1. Using Pythagoras Theorem...

= 30^2 + 30^2 = 1,800 (30^2=900 so you've added 2 of those to make 1,800)

= SQUARE ROOT THE ANSWER OF 1,800

\sqrt{x} 1,800= 42.42640687119285‬

TO GET A MORE PRECISE ANSWER WE ROUND IT UP TO 1 decimal place

= 42.4 yd is the diagonal length of the dance floor!!

HOPE THIS HELPS!!

6 0
3 years ago
Mason wants to play with Maliyah's Doll House, but first he needs to stop at the clubhouse. If all
denis23 [38]

Answer:6,8,14

Step-by-step explanation:

Just did it on math nation

6 0
3 years ago
Read 2 more answers
Find f(x) and g(x) so that the function can be described as y = f(g(x)). <br><br> y = 7/sqrt 8x +10
Blizzard [7]
Assuming you meant

y =  \frac{7}{ \sqrt{8x+10} }

Then you can compose the function g(x)

g(x)= \sqrt{8x+10}

With the function

f(x)= \frac{7}{x}


Because f (g(x) ) means that you first find (calculte)     \sqrt{8x+10}       and second you divide 7 by g(x) to obtain 7 / [√(8x+10) ].
8 0
3 years ago
How many solutions would it have none infinite or one ?
Jlenok [28]

Answer:

c

Step-by-step explanation:

c

8 0
2 years ago
Read 2 more answers
Can I get some help please? <br><br><br> Thanks!
quester [9]
An ellipse (oval shape) is expressed by the following equation:

\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2}=1 where h is the x coordinate of the center and k is the y coordinate of the center. Furthermore, a is the horizontal distance from the center, and b is the vertical distance from the center. Lastly, c is the distance from the center to one of the foci (they are spaced apart equally).

We can find the foci by using a^2 - b^2 = c^2

36 - 11 = c^2

c =  \sqrt{25}  = 5

Since the k value in this case is 0, the y value of both foci are 0. Also, since h and k are both 0, we know the center of the ellipse is at the origin.

So the foci are (-5, 0) and (5, 0)

Hope this helps :)

3 0
3 years ago
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