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disa [49]
3 years ago
11

Find the sine, cosine and tangent for 15 degrees

Mathematics
1 answer:
suter [353]3 years ago
7 0
Sin(15) = 0.258819045103
cos(15) = 0.965925826289
tan(15) = 0.267949192431
all you do is get a graphing calculator input sin(15), then cos(15), and tan(15), make sure the calculator is in degrees not radians hit enter or what ever the answer button is and it should tell you your answer 
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Use the zero product property to find the solutions to the equation 2x2 + x-1 = 2
algol [13]

Answer:

see explanation

Step-by-step explanation:

Given

2x² + x - 1 = 2 ( subtract 2 from both sides )

2x² + x - 3 = 0

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 2 × - 3 = - 6 and sum = + 1

The factors are - 2 and + 3

Use these factors to split the x- term

2x² - 2x + 3x - 3 = 0 ( factor the first/second and third/fourth terms )

2x(x - 1) + 3(x - 1) = 0 ← factor out (x - 1) from each term

(x - 1)(2x + 3) = 0

Equate each factor to zero and solve for x

x - 1 = 0 ⇒ x = 1

2x + 3 = 0 ⇒ 2x = - 3 ⇒ x = - \frac{3}{2}

3 0
3 years ago
Read 2 more answers
Find the discriminant of the following equation.<br> 4x2 + 16x + 16 = 0 ...?
Alexxandr [17]
To find the discriminant of the following equation you have to remember tha main formula :  ax^2 +bx + c and the one for discriminant is  <span>b^2 -4ac
So, now we can solve it </span>16^2 -4(16)(4) = 4^2-4(4)
(4^2)^2 -4(4)(4)(4)-4^2 +4(4) = 0
4^4 - 4^4 = 016^2-4*4*16=0 , so the discriminants is 0 :) 
Hope it's clear!
8 0
3 years ago
Read 2 more answers
If F(x) = 2x^ln(x), then F'(2) =
pantera1 [17]

Answer:

eln2(x)ln(x4)/x

I HOPE THIS HELPED!

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
Recall that m(t) = (1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500g sample of phosphorus-32 decays
katrin2010 [14]

The question is incomplete, here is the complete question:

Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.

<u>Answer:</u> The half life of the sample of phosphorus-32 is 14.28days^{-1}

<u>Step-by-step explanation:</u>

The equation used to calculate the half life of the sample is given as:

m(t)=m_o(1/2)^{t/h}

where,

m(t) =  amount of sample after time 't' = 356 g

m_o = initial amount of the sample = 500 g

t = time period = 7 days

h = half life of the sample = ?

Putting values in above equation, we get:

356=500\times (\frac{1}{2})^{7/h}\\\\h=14.28days^{-1}

Hence, the half life of the sample of phosphorus-32 is 14.28days^{-1}

7 0
4 years ago
Please help I keep getting this wrong
slamgirl [31]
X/4 < = -3/2...multiply both sides by 4
x < = -3/2 * 4
x < = -12/2
x < = -6.......graph : 1 (because less then shades to the left....and an equal sign in the problem means the dot is solid)

7x/9 > - 14/3 ....multiply both sides by 9
7x > - 14/3 * 9
7x > -42...divide both sides by 7
x > -42/7
x > - 6......graph : 4 (because greater then shades to the right...and no equal sign means it is an open dot)

-75x/4 > 225/2...multiply both sides by 4
-75x > 225/2 * 4
-75x > 450...divide both sides by -75, and change the sign
x < -450/75
x < - 6.......graph : 2 (because less then is shaded to the left...and no equal sign means an open dot)

2x/3 > -16/3...multiply both sides by 3
2x > -16/3 * 3
2x > -16 ...divide both sides by 2
x > -16/2
x > -8......graph : 3 (because greater then shades to the right....and no equal sign means an open dot)








4 0
3 years ago
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