Answer:
The inequality is 12.5v + 70 ≥ 215
and the amount of visits they can make is 12 visits
Step-by-step explanation:
if you take away (subtract) 70 from both sides, you'll get
12.5v ≥ 145
and when you divide both sides by 12.5, you'll get 11.6, or 12
Answer:
The answer is below
Step-by-step explanation:
The linear model represents the height, f(x), of a water balloon thrown off the roof of a building over time, x, measured in seconds: A linear model with ordered pairs at 0, 60 and 2, 75 and 4, 75 and 6, 40 and 8, 20 and 10, 0 and 12, 0 and 14, 0. The x axis is labeled Time in seconds, and the y axis is labeled Height in feet. Part A: During what interval(s) of the domain is the water balloon's height increasing? (2 points) Part B: During what interval(s) of the domain is the water balloon's height staying the same? (2 points) Part C: During what interval(s) of the domain is the water balloon's height decreasing the fastest? Use complete sentences to support your answer. (3 points) Part D: Use the constraints of the real-world situation to predict the height of the water balloon at 16 seconds.
Answer:
Part A:
Between 0 and 2 seconds, the height of the balloon increases from 60 feet to 75 feet at a rate of 7.5 ft/s
Part B:
Between 2 and 4 seconds, the height stays constant at 75 feet.
Part C:
Between 4 and 6 seconds, the height of the balloon decreases from 75 feet to 40 feet at a rate of -17.5 ft/s
Between 6 and 8 seconds, the height of the balloon decreases from 40 feet to 20 feet at a rate of -10 ft/s
Between 8 and 10 seconds, the height of the balloon decreases from 20 feet to 0 feet at a rate of -10 ft/s
Hence it fastest decreasing rate is -17.5 ft/s which is between 4 to 6 seconds.
Part D:
From 10 seconds, the balloon is at the ground (0 feet), it continues to remain at 0 feet even at 16 seconds.
For this case we have that the main function is given by:

We apply the following transformation:
Vertical displacements:
Assume k> 0
To graph y = f (x) - k, move the graph k units down.
For k = 3 we have:

Answer:
when the function is changed to f (x) - 3 the change that will occur is:
Vertical displacement 3 units down.
Answer:
t = 4 seconds
Step-by-step explanation:
The height of the projectile after it is launched is given by the function :

t is time in seconds
We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0
So,

The above is a quadratic equation. It can be solved by the formula as follows :

Here, a = -16, b = 32 and c = 128

Neglecting negative value, the projectile will land after 4 seconds.