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Alex
3 years ago
12

Lian is deciding which of two gyms to join. Each gym charges a monthly rate plus a one-time membership fee.

Mathematics
2 answers:
amm18123 years ago
8 0

Answer:

The answer is C on edge.

Step-by-step explanation:

same monthly rate and same membership fee

BartSMP [9]3 years ago
6 0
The conclusion is that both gym charge the same, because the identity 75 = 75 means that the two equations are equivalent (the same).
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Solve the whole problem i give brainliest please help me.
Anna11 [10]

Answer:

The inequality is 12.5v + 70 ≥ 215

and the amount of visits they can make is 12 visits

Step-by-step explanation:

if you take away (subtract) 70 from both sides, you'll get

12.5v ≥ 145

and when you divide both sides by 12.5, you'll get 11.6, or 12

3 0
3 years ago
The following 5 keys are for the following 5 locked padlocks. Each key opens one and only one padlock. Different keys open diffe
Scilla [17]

{5}^{5}

is the answer.

7 0
3 years ago
50 POINTS
mamaluj [8]

Answer:

The answer is below

Step-by-step explanation:

The linear model represents the height, f(x), of a water balloon thrown off the roof of a building over time, x, measured in seconds: A linear model with ordered pairs at 0, 60 and 2, 75 and 4, 75 and 6, 40 and 8, 20 and 10, 0 and 12, 0 and 14, 0. The x axis is labeled Time in seconds, and the y axis is labeled Height in feet. Part A: During what interval(s) of the domain is the water balloon's height increasing? (2 points) Part B: During what interval(s) of the domain is the water balloon's height staying the same? (2 points) Part C: During what interval(s) of the domain is the water balloon's height decreasing the fastest? Use complete sentences to support your answer. (3 points) Part D: Use the constraints of the real-world situation to predict the height of the water balloon at 16 seconds.

Answer:

Part A:

Between 0 and 2 seconds, the height of the balloon increases from 60 feet to 75 feet  at a rate of 7.5 ft/s

Part B:

Between 2 and 4 seconds, the height stays constant at 75 feet.

Part C:

Between 4 and 6 seconds, the height of the balloon decreases from 75 feet to 40 feet at a rate of -17.5 ft/s

Between 6 and 8 seconds, the height of the balloon decreases from 40 feet to 20 feet at a rate of -10 ft/s

Between 8 and 10 seconds, the height of the balloon decreases from 20 feet to 0 feet at a rate of -10 ft/s

Hence it fastest decreasing rate is -17.5 ft/s which is between 4 to 6 seconds.

Part D:

From 10 seconds, the balloon is at the ground (0 feet), it continues to remain at 0 feet even at 16 seconds.

3 0
3 years ago
Given the parent function of f(x) = x3, what change will occur when the function is changed to f(x) − 3?
DedPeter [7]

For this case we have that the main function is given by:

f (x) = x ^ 3

We apply the following transformation:

Vertical displacements:

Assume k> 0

To graph y = f (x) - k, move the graph k units down.

For k = 3 we have:

y = f (x) - 3\\y = x ^ 3 - 3

Answer:

when the function is changed to f (x) - 3 the change that will occur is:

Vertical displacement 3 units down.

5 0
3 years ago
Read 2 more answers
A projectile is launched into the air. The function h(t) = –16t2 + 32t + 128 gives the height, h, in feet, of the projectile t s
Zinaida [17]

Answer:

t = 4 seconds

Step-by-step explanation:

The height of the projectile after it is launched is given by the function :

h(t)=-16t^2+32t+128

t is time in seconds

We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0

So,

-16t^2+32t+128=0

The above is a quadratic equation. It can be solved by the formula as follows :

t=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}

Here, a = -16, b = 32 and c = 128

t=\dfrac{-32\pm \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=\dfrac{-32+ \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}, \dfrac{-32\- \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=-2\ s\ \text{and}\ 4\ s

Neglecting negative value, the projectile will land after 4 seconds.

4 0
3 years ago
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