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antoniya [11.8K]
3 years ago
5

How is using the x-factor helpful in solving quadratic equations? provide examples and explain why?

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
5 0
The dog ran across the yard and barked :)

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Write an expression for the area of the shaded region in its simplest form. Show all of your steps.
netineya [11]
The area of the shaded region is going to be the area of the rectangle minus the area of the square.

Area of a rectangle is L * W.
A = L * W
A = (x + 10)(2x + 5)
A = x(2x + 5) + 10(2x + 5)
A = 2x^2 + 5x + 20x + 50
A = 2x^2 + 25x + 50 .....this is the area of the rectangle

area of a square is : A = a^2...where a is one side
A = (x + 1)^2
A = (x + 1)(x + 1)
A = x(x + 1) + 1(x + 1)
A = x^2 + x + x + 1
A = x^2 + 2x + 1

now we subtract the area of the square from the area of the rectangle to get the area of the shaded region.

2x^2 + 25x + 50 - (x^2 + 2x + 1) =
2x^2 + 25x + 50 - x^2 - 2x - 1 =
x^2 + 23x + 49 <== the area of the shaded region
6 0
3 years ago
Can someone please help me with this question. I just need to know the height.
Lady_Fox [76]

Step-by-step explanation:

Area of triangle = 1/2 . base . height

4 0
3 years ago
Which is the equation of a parabola with vertex (0, 0), that opens to the left and
andrezito [222]

Answer:

Step-by-step explanation:

I'm going to guess that the square  exponents are on the top y's   only?   then answer b) looks good

8 0
3 years ago
Read 2 more answers
Write in lowest terms:<br> 9/(15x)
liq [111]

Answer:

Step-by-step explanation:

3x - 25

 ———————

    5  

Should be something similar to that, sorry If i couldn't help much.

6 0
3 years ago
Triangle FGH is similar to JKM.
mario62 [17]

Answer: J = 14.4 cm

Step-by-step explanation:

<em>K is similar to G</em>

So we can find the scale that FHG was dilated by dividing the side length of G by the side length of K

16.56/9.2 = 1.8

So the sides of the triangle KMJ were multiplied by a factor of 1.8

to find m :

25.92/1.8 = 14.4

J = 14.4

8 0
3 years ago
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