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4 years ago

How do I find the difference on th mean

Mathematics

1 answer:

azamat4 years ago

7 0

I think there talking about the difference between the mean and the range or does it talk about the range.

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Find the cosine of ∠J.

RUDIKE [14]

Answer:

$\cos = \frac{base}{hypotenuse} = \\ \cos(j) = \frac{ \sqrt{29} }{ \sqrt{94} } = \sqrt{ \frac{29}{94} } \\ answer = \sqrt{ \frac{29}{94} }$

6 0

3 years ago

Topic 1: Translate<br><br> The sum of twice a number and 9 is -25."

Vinvika [58]

Answer:

2n + 9 = - 25

Step-by-step explanation:

let the number be n then twice the number is 2n

The sum of 2n and 9 is 2n + 9

the result is - 25 , that is

2n + 9 = - 25

7 0

2 years ago

Read 2 more answers

Reflect (5,-5) in (a) the x-axis and (b) the y-axis.

astraxan [27]

Answer:

a. (5,5)

b. (-5,-5)

Step-by-step explanation:

reflection over x-axis flips the sign of y-coordinate

reflection over y-axis flips the sign of x-coordinate

6 0

3 years ago

Need help with question 7

Sholpan [36]

Answer:

There are two orders in which we can do the steps:

1. GAFDC

2. GABEC

Step-by-step explanation:

$4x-8=5x-2(x+2)$

Step 1 :G Using distributive property to remove parenthesis:

$4x-8=5x+(-2\times x-2\times2)$

$4x-8=5x-2x-4$

Step 2:A Collect like terms:

$4x-8=3x-4$

Step 3: F Add 8 to both sides:

$4x-8+8=3x-4+8$

$4x=3x+4$

Step 4: D Subtract $3x$ from both sides:

$4x-3x=3x+4-3x$

$x=4$

Solution:C

$x=4$

$4x-8=5x-2(x+2)$

Step 1 :G Using distributive property to remove parenthesis:

$4x-8=5x+(-2\times x-2\times2)$

$4x-8=5x-2x-4$

Step 2:A Collect like terms:

$4x-8=3x-4$

Step 4: B Subtract $3x$ from both sides:

$4x-8-3x=3x-4-3x$

$x-8=-4$

Step 3: E Add 8 to both sides:

$x-8+8=-4+8$

$x=4$

Solution:C

$x=4$

There are two orders in which we can do the steps:

1. GAFDC

2. GABEC

4 0

3 years ago

Find the standard form of the equation of the ellipse with the given characteristics and center at the origin. Foci: (±7, 0); ma

n200080 [17]

Answer: $\dfrac{x^2}{81}+\dfrac{y^2}{32}=1$

Step-by-step explanation:

The standard form of equation of ellipse with foci (±c,0) as:

$\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1$

, where major axis = 2a and minor axis = 2b

Given: Foci: (±7, 0); major axis of length 18

i.e. c= 7 and 2a =18 ⇒a= 9

Also,

$c^2=a^2-b^2\Rightarrow\ b^2= a^2-c^2\\\\\Rightarrow\ b^2={9^2-7^2}={81-49}\\\\\Rightarrow\ b^2=32$

Put value of $a^2$ and $b^2$ , we get the required equation :

$\dfrac{x^2}{81}+\dfrac{y^2}{32}=1$

4 0

4 years ago