Answer:
The volume of the cylinder is decreasing at a rate of 83629.2 m³/h.
Step-by-step explanation:
The volume of a is given by:

Where:
r: is the radius = 55 m
h: is the height = 88 m
We can express the rate of change of the volume of the cylinder as follows:
![\frac{dV}{dt} = \pi[h\frac{2rdr}{dt} + r^{2}\frac{dh}{dt}]](https://tex.z-dn.net/?f=%20%5Cfrac%7BdV%7D%7Bdt%7D%20%3D%20%5Cpi%5Bh%5Cfrac%7B2rdr%7D%7Bdt%7D%20%2B%20r%5E%7B2%7D%5Cfrac%7Bdh%7D%7Bdt%7D%5D%20)
If dr/dt = 11 m/h and dh/dt = -44m/h, we have:
![\frac{dV}{dt} = \pi[88 m*2*55 m*11 m/h + (55 m)^{2}*(-44 m/h)] = -83629.2 m^{3}/h](https://tex.z-dn.net/?f=%20%5Cfrac%7BdV%7D%7Bdt%7D%20%3D%20%5Cpi%5B88%20m%2A2%2A55%20m%2A11%20m%2Fh%20%2B%20%2855%20m%29%5E%7B2%7D%2A%28-44%20m%2Fh%29%5D%20%3D%20-83629.2%20m%5E%7B3%7D%2Fh%20)
Therefore, the volume of the cylinder is decreasing at a rate of 83629.2 m³/h.
I hope it helps you!
So the original price is "x".
the discounted price by 10% is P(x) = 0.9x.
the price minus a $150 coupon is C(x) = x - 150.
so, if you go to the store, the item is discounted by 10%, so you're really only getting out of your pocket 90% of that, or 0.9x, but!!! wait a minute!! you have a $150 coupon, and you can use that for the purchase, so you're really only getting out of your pocket 0.9x - 150, namely the discounted by 10% and then the saving from the coupon.
C( P(x) ) = P(x) - 150
C( P(x) ) = 0.9x - 150
<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em> </em><em>.</em><em>.</em><em>.</em>
Answer:
3rd option
Step-by-step explanation:
the ratio of b : c is the cos77° , that is
cos77° =
=
≈ 0.224951054.