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There are two ways to find or determine for the value of
c. In the first method, we can use addition and subtraction to isolate the
variable c from the other variables. In the second method, we can use the
transposition of variables to isolate the variable c from the other variables.
So solving for the value of c:
<span>Using 1st method: Addition and Subtraction</span>
We are given:
240 = 6 z + c
Simply subtract 6 z on both sides:
240 – 6 z = 6 z + c – 6 z
Cancelling 6 z – 6 z on the right side:
240 – 6 z = c
or
c = 240 – 6 z
<span>Using the 2nd method: Transposition</span>
240 = 6 z + c
What we are going to do here is to simply transpose the
variable 6 z from the right side to the left side of the equation so that we
are left with c alone on the right side. Always remember that when we
transpose, the symbol becomes opposite. That is:
240 + (- 6 z) = c
240 – 6 z = c
or
<span>c = 240 – 6 z</span>
(2y² + 7y + 11) - (8y² - 5y + 7) you can distribute the negative sign to the second expression and then combine the like terms
new expression: (2y² + 7y + 11) (-8y² + 5y - 7)
2y² and -8y² equals -6y²
7y and 5y equals 12y
11 and -7 equals 4
The answer is -6y² + 12y + 4
Answer:
the domain is : D = ]-∞ , -5[ U ]-5 , -3[ U ]-3 , +∞[
Step-by-step explanation:
hello :
f(x) = 9x/(x+5)(x+3)
f exist for : (x+5)(x+3) ≠ 0
(x+5)(x+3)=0
x+5=0 or x+3=0 means : x= - 5 or x= -3
the domain is : D = ]-∞ , -5[ U ]-5 , -3[ U ]-3 , +∞[
