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3 years ago

If f(x) = 3x + 2 and

Mathematics

1 answer:

WARRIOR [948]3 years ago

5 0

Answer:

Step-by-step explanation:

(f - g)(x) = f(x) - g(x)

f(x) = 3x + 2, g(x) = 2x - 2.

Substitute:

(f - g)(x) = (3x + 2) - (2x - 2) = 3x + 2 - 2x - (-2) = 3x + 2 - 2x + 2

combine like terms

(f - g)(x) = (3x - 2x) + (2 + 2) = x + 4

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How to write 1/12 as a decimal with long division?

Leto [7]

To write 1/12 as a decimal you would do 1 divided by 12. 1 goes into 12 0 times, giving you a 0 in the ones place. You would the do 120 divided by 12, giving you 10. Therefore, 1/12 as a decimal is 0.10, simplified to 0.1

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3 years ago

Shera is building a cabinet. She is making wooden braces for the corners of the cabinet. Find the surface area of each brace. 1

ahrayia [7]

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3 years ago

how do you put 100,000 years in word form? (like a century, decade, millennium, etc) I will give you branliest answer if you can

natima [27]

Answer:

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3 years ago

Read 2 more answers

The diagram shows several planes, lines, and points.

Aleksandr-060686 [28]

Answer:

The true statement is Line h has points on planes R, P, and T

Step-by-step explanation:

The rest of the question is the attached figure

According to the graph, we will check which option is true.

a. Line h intersects line f at two points, A and B (Wrong)

Because: h intersects line f at B only.

b. Line h is the intersection of planes R and T (Wrong)

Because: g is the intersection of planes R and T

c. Line h intersects plane P at point C (Wrong)

Because: h intersects plane P at point B

d. Line h has points on planes R, P, and T (True)

Because h has the point B on the plane P, h has the point A on the plane T

and the points of h on the plane R

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3 years ago

Quadrilateral PQRS is a square whos side length is 10. Let X and Y be points outside the square so that XQ = YS = 6 and XP = YR

erik [133]

Answer:

392

Step-by-step explanation:

Triangles XQP and YRS are right triangles because triples 6, 8, 10 are Pythagorean triples.

Extend lines XQ, YR, YS and XP and mark their intersection as A and B.

Quadrilateral XAYB is a square because all right triangles PXQ, QAR, RYS and SBP are congruent (by ASA postulate) and therefore

all angles of the quadrilateral XAYB are right angles

all sides of XAYB are congruent and equal to 6 + 8 = 14 units.

Segment XY is the diagonal of the square XAYB, by Pythagorean theorem,

$XY^2=XA^2+AY^2\\ \\XY^2=14^2+14^2\\ \\XY^2=196+196\\ \\XY^2=392$

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3 years ago