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3 years ago

What is the classifications of polynomials -gh4i+3g5

Mathematics

1 answer:

Step2247 [10]3 years ago

5 0

Answer:

The polynomial -gh⁴i + 3g⁵ is a binomial, since it has two terms

Degree of polynomial: degree of a polynomial is the term with highest of exponent.

Degree of binomial -gh⁴i + 3g⁵ = 6

1st term(-gh⁴i ) = (power of g = 1, power of h = 4, power of i = 1)

2nd term(3g⁵) = (power of g = 5)

the polynomial -gh⁴i + 3g⁵ is a 6 degree binomial.

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If I multiply any number by 1 whole, my product will be:

marusya05 [52]

Let a = any number

So, 1 times a = a.

In other words, any number times 1 = any number.

Two samples:

1. 45 x 1 = 45

2. -567 x 1 = -567

Understand?

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3 years ago

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Tamara bought 4 pack of move tickets $42.50 .How much does the single ticket cost. (3)which digit is in the hundreds

8_murik_8 [283]

$42.50 divided by 4 is 10.625
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3 years ago

A 5.00 L air sample has a pressure of 107 kPa at a temperature of -50C. If the temperature is raised to 102C and the volume expa

joja [24]

Answer:

129.9 kPa

Step-by-step explanation:

The relationship between temperature T, volume V and pressure P is given by the ideal gas equation which is given as

K = PV/T where K is a constant such that were there is a change of temperature T₁, volume V₁ and pressure P₁ to temperature T₂, volume V₂ and pressure P₂ then the relationship may be given

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where T is measured in ⁰K

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3 years ago

A block with a mass of 10 kg is being pushed. its acceleration is 5 m/s.s . Calculate the force acting on the block ? plz answer

Hitman42 [59]

Answer:

<h3>The answer is 50 N</h3>

Step-by-step explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

<h3>force = mass × acceleration</h3>

From the question

mass = 10 kg

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We have the final answer as

Hope this helps you

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3 years ago

Consider the random experiment of tossing 3 fair coins and observing how many of them come to rest with the heads side of the co

zaharov [31]

Answer:

b. S = AUB

Step-by-step explanation:

Since the coins are tossed 3 times and each coin has head, H and tail, T(2 sides), the sample space is S = 2 × 2 × 2 = 2³ = 8

All the possible outcomes are HTT, HHT, HHH, THH, TTH, HTH,THT and TTT

Since S denote the sample space

S = {HTT, HHT, HHH, THH, TTH, HTH,THT, TTT}

Since A denote the event that at least 1 of the coins comes to rest with its heads side upwards, the possible outcomes are HTT, HHT, HHH, THH, TTH, HTH and THT

So, A = {HTT, HHT, HHH, THH, TTH, HTH,THT}

Also B denote the event that none of the coins comes to rest with its heads side upwards, that is no heads. The possible outcome is TTT

So, B = {TTT}

Since S denote the sample space

S = {HTT, HHT, HHH, THH, TTH, HTH,THT, TTT}

So, A ∪ B = {HTT, HHT, HHH, THH, TTH, HTH,THT} ∪ {TTT} = {HTT, HHT, HHH, THH, TTH, HTH,THT, TTT} = S

So, S = A ∪ B

So, S = A ∪ B does not denote an abuse of notation.

The answer is b.

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3 years ago