The graph shows the system y=2x+1 y=2x^2+1 Which ordered pairs are solutions of the system?

Mathematics

1 answer:

zhenek [66]3 years ago

3 0

Hey!

To solve this problem, we would really have to graph both equations.

OPEN THE FIRST IMAGE

The first image I provided was the image of this equation graphed: y=2x+1

OPEN THE SECOND IMAGE

The second image I provided was the image of this equation graphed: y=2x^2+1

PLEASE DO NOT LOOK AT THE THIRD IMAGE YET!

The first image has two points. One at ( -0.5, 0 ) and the other at ( 0, 1 ).

The second image has only one point, which is at ( 0, 1 ).

OPEN THE THIRD IMAGE

Now, when both are combined we see that they intersect at two points, which are ( 0, 1 ) and ( 1, 3 ).

So, our answer is...

The ordered pairs that are the solution to the system are ( 0,1 ) and ( 1,3 ).

Hope this helped!

- Lindsey Frazier ♥

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gulaghasi [49]

The bearing of the plane is approximately 178.037°. $\blacksquare$

<h3>Procedure - Determination of the bearing of the plane</h3><h3 />

Let suppose that bearing angles are in the following standard position, whose vector formula is:

$\vec r = r\cdot (\sin \theta, \cos \theta)$ (1)

Where:

$r$ - Magnitude of the vector, in miles per hour.
$\theta$ - Direction of the vector, in degrees.

That is, the line of reference is the $+y$ semiaxis.

The resulting vector ( $\vec v$ ), in miles per hour, is the sum of airspeed of the airplane ( $\vec v_{A}$ ), in miles per hour, and the speed of the wind ( $\vec v_{W}$ ), in miles per hour, that is:

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If we know that $v_{A} = 239\,\frac{mi}{h}$ , $\theta_{A} = 180^{\circ}$ , $v_{W} = 10\,\frac{m}{s}$ and $\theta_{W} = 53^{\circ}$ , then the resulting vector is: