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natulia [17]
3 years ago
10

Nicole bought a bag containing assorted hard candies from the local corner store. They were on clearance and she got a good deal

. All the candies are the same size and shape but they are different colors and flavors. There are two blue ones, four red ones, six purple ones, fourteen green ones, and ten orange ones. If the bag is shaken really well to mix the candy in the bag, what is the probability ( as a fraction) that the first candy she pulls out of the bag will not be green?
Mathematics
1 answer:
Tresset [83]3 years ago
8 0

Answer:

P = \frac{1}{2}

Step-by-step explanation:

2 blue

4 red

6 purple

14 green

There are 26 candies overall.

\frac{2+4+6}{24} =

\frac{12}{24} =

\frac{1}{2}

The probability of her not pulling a green candy is \frac{1}{2} chance

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When 238 is divided by the natural number n, the quotient is 3 more than n, and there is no remainder. What is n?
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Answer:

n = 14

Step-by-step explanation:

Write the equation in algebraic (numbers and symbols) form

\frac{238}{n} = n + 3              Rearrange the equation

n\frac{238}{n} = n(n + 3)           Multiply both sides by 'n'

238 = n(n + 3)          On the left, multiplying and dividing by 'n' cancels out

238 = n² + 3n           Distributed right side

0 = n² + 3n - 238        Rearranged to standard form for quadratic equations

Remember standard form for quadratic equations is: ax² + bx + c = 0

State the variables a, b and c:

a = 1; b = 3; c = -238

When a quadratic equation is in standard form, you can <u>use the quadratic formula</u> to solve for 'n'. (Usually, you see the variable 'x', but the quadratic formula can solve for 'n' as if it is 'x', as long as it's in standard form.)

n = \frac{-b±\sqrt{b^{2}-4ac}}{2a}  (ignore the Â, it's a formatting error)

n = \frac{-(3)±\sqrt{(3)^{2}-4(1)(-238)}}{2(1)}  Substitute the values for 'a', 'b' and 'c' from the equation

n = \frac{-3±\sqrt{9-(-952)}}{2}     In the root, two negatives make a positive

n = \frac{-3±\sqrt{9+952}}{2}     Add inside the root

n = \frac{-3±\sqrt{961}}{2}       Find the square root of 961

n = \frac{-3±{31}{2}     Split the equation at the ±

Split for adding:

n = \frac{-3+31}{2}    Simplify

n = 14

Split for subtracting:

n = \frac{-3-31}{2}      Simplify

n = -17

You get the answers 14 and -17 for 'n'. Decide which one is 'inadmissible', meaning it can't be right even if it solves the equation.

The problem says 'n' is a natural number. <u>Natural numbers are all non-partial numbers count up from 1.</u> (Non-partial means as a fraction, they are reduced to a number over 1). Since -17 is less than 1, it is inadmissible because it is not a natural number.

Therefore, 'n' is 14.

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3 years ago
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