The line integral is the path of the function along a line having a continuous value.
The integral solved gives the value 111.
The given question is
where C is the line from (1, 0, 0) to (4, 1, 3)
Here
x→ 1⇒ 4
y→ 0⇒1
z→ 0⇒ 3
Let t be defined be the range 0≤ t ≤ 1
Then x= 4t+1 : dx= 4dt
y= t ": dy= dt
z= 3t : dz= 3dt
Putting the values
= [36(1)²- 36(0)²]+ 3 [16(1)² +1+8(1)] - 3 [16(0)² +1+8(0)] + [3(1)²- 3(0)² ]
= 36 +75-3+3
= 111
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Well, it cost Dave $210 dollars for three hours. So a 20% tip would be $42, so all together Dave spent $252 on the limousine and tip.
Answer:
3
Step-by-step explanation:
Divide 24 by 4 = 6
Divide 2 by 6 = 3
Answer:
-898,560c
Step-by-step explanation:
(c)52×(-1)9×(-2)×32×(-10)3
=52c×(-9)×(-64)×(-30)
=52c×(-17,280)
= -898,560c
Answer:
-2 9/10, -1.8, -5/3, -0.9, 2/10, 11/10, 2.3, 10/4
Step-by-step explanation:
