Answer:
(x + 2)^2 + (y - 5)^2 = 32 or [4√2]^2
Step-by-step explanation:
Here we have a circle with center at (-2, 5), which represents (h, k). Thus, the standard equation of a circle with center at (h, k), shown below
(x - h)^2 + (y - k)^2 = r^2 (where r represents the radius of the circle)
becomes:
(x + 2)^2 + (y - 5)^2 = r^2. We know that this circle passes through (-6, 1), so this last equation becomes:
(-6 + 2)^2 + (1 - 5)^2 = r^2, or 16 + 16 = r^2.
Then 2(16) = r^2.
Taking the square root of both sides yields r = 4√2.
The desired equation of this circle is then
(x + 2)^2 + (y - 5)^2 = 32 or [4√2]^2
Addition,subtraction,and multiplication
Answer:
$400=75 + 4t
82 tickets must be sold to fund the dance
Let, the numbers = x, y
It is given that: x + y = -7
2x + 70 = 6
2x = 6 - 70
x = -64/2
x = -32
Substitute it in first equation:
-32 + y = -7
y = -7 + 32
y = 25
In short, Your Numbers are: -32 and 25
Hope this helps!
Answer:
x = 1 ± √89
Step-by-step explanation:
Step 1: Expand
x² - 2x - 63 = 25
Step 2: Isolate xs
x² - 2x = 88
Step 3: Complete the square
x² - 2x + 1 = 88 + 1
(x - 1)² = 89
Step 3: Square root both sides
√(x - 1)² = ±√89
x - 1 = ±√89
Step 4: Isolate x
x = 1 ± √89