Of course! so basically for each value of x, for example -6, plug it into the equation. so for -6 do -2/3(-6)+7. hope this helps!
You have to divide 53 with 4 students making them each get 13 bars each
The question is incomplete.
The complete question is:
Given the functions j(x) = x² − 9 and k(x) = −x + 7, which operation results in a 3rd degree polynomial?
Answer: the multiplication of j(x) and k(x)
Explanation:
<span>1) j(x) × k(x) = (</span><span>x² − 9) ( − x + 7)</span>
<span>2) Use distributive propery:
</span>
<span>(<span>x²)(- x) + (x²) (7) + (-9)(-x) + (− 9) ( 7) = - x³ + 7x² + 9x - 63
</span></span><span><span>
</span></span><span><span>
</span></span><span><span>The exponent of x is 3, hence this is a third degree polynomial.
</span></span>
A is your answer since the x values change at a rate of +1 and the y values change at a rate of +4
