Answer:
x . 0.3
y . 0.4
Step-by-step explanation:
please mark me brainliest please
First you cancel 7 and 28, and 3 and 9, so that leaves you with 4/3 x 15/17, then you cancel 3 and 15 so you get 4x5/17 which should give you 20/17!
Answer:
The series is absolutely convergent.
Step-by-step explanation:
By ratio test, we find the limit as n approaches infinity of
|[a_(n+1)]/a_n|
a_n = (-1)^(n - 1).(3^n)/(2^n.n^3)
a_(n+1) = (-1)^n.3^(n+1)/(2^(n+1).(n+1)^3)
[a_(n+1)]/a_n = [(-1)^n.3^(n+1)/(2^(n+1).(n+1)^3)] × [(2^n.n^3)/(-1)^(n - 1).(3^n)]
= |-3n³/2(n+1)³|
= 3n³/2(n+1)³
= (3/2)[1/(1 + 1/n)³]
Now, we take the limit of (3/2)[1/(1 + 1/n)³] as n approaches infinity
= (3/2)limit of [1/(1 + 1/n)³] as n approaches infinity
= 3/2 × 1
= 3/2
The series is therefore, absolutely convergent, and the limit is 3/2
Based on the information in the table, an example of independent events is the: P(policer officer and chooses car).
<h3>What is an
independent event?</h3>
An independent event can be defined as an event that isn't dependent on other events. Thus, it isn't affected by any previous event.
Based on the information provided, we can infer and logically deduce that an example of independent events is the probability of being a policer officer and chooses a car because they aren't overlapping probabilities.
Read more on independent events here: brainly.com/question/26795996
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Answer:
You didn't give the expression whose zero you want to find. From the options you wrote, the expression has two zeros, this means it is a quadratic expression.
I will however explain how to find the zero of a quadratic expression.
Step-by-step explanation:
An expression is called quadratic, if the highest degree of the variable is 2, no more, no less. It is of the form: ax² + bx + c, where a, b, and c are constants.
The zeros of a quadratic expression are the values that make the expression vanish, that is equal to zero.
Example: Find the zeros of 2x² - 6x + 4
First, equate the expression to zero
2x² - 6x + 4 = 0
Next, solve for x
2x² - 2x - 4x + 4 = 0
2x(x - 1) - 4(x - 1) = 0
(2x - 4)(x - 1) = 0
(2x - 4) = 0
Or
(x - 1) = 0
2x - 4 = 0
2x = 4
=> x = 4/2 = 2
Or
x - 1 = 0
x = 1
Therefore, the zeros of the polynomial are 1 and 2.
